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lana [24]
3 years ago
10

The line representing a proportional relationship always goes through the point (0,0). If x is zero, multiplying x by the consta

nt will always give you 0 for y. Try it with our ice cream example. Make the independent variable, number of scoops, 0. The constant is 2. 0 × 2 = 0. The dependent variable is also 0. What other point will appear on the line representing this proportional relationship where the constant of proportionality is 2? A (1,3) B (2, 4) C (2, 2) D (4, 2)
Mathematics
1 answer:
Sidana [21]3 years ago
3 0

Answer:

B (2, 4)

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

In this problem the constant of proportionality k is given and is equal to

k=2

so

The linear equation is given by

y=2x

That means ----> the y-coordinate is two times the x-coordinate

therefore

The other point is B(2.4)

Because

For x=2, y=4

the y-coordinate is two times the x-coordinate

4=2(2)\\4=4

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hello,

i advice you check the question again if it is GF(2^{4}) or GF(24). i believe the question should rather be in this form;

multiplication in GF(2^{4}): Compute A(x)B(x) mod P(x) = x^{4} + x+1, where A(x)=x^{2}+1, and B(x)=x^{3} + x+1.

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A(x)B(x)=(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1  ) = (x^{5} +x^{3}+x^{2}  ) + (x^{3}+x+1  ) mod (x^{4} + x+1 )

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