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Luden [163]
3 years ago
10

HELP I WILL GIVE BRAINLIEST!

Mathematics
1 answer:
bearhunter [10]3 years ago
3 0

Answer:

Cant see the grapg but i would guess and say C(2014) i guess

Step-by-step explanation:

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Fill in the box to rewrite the expression 5x + 10<br> using the GCF.<br> 5x + 10 = (<br> x) + (5 •
zvonat [6]
The GCF is 5 so the new expression would be: 5(x+2)
7 0
2 years ago
5x - 2y = 3, -5x + 4y = 9 solutions
Vinvika [58]
5x-2y=3
-5x+4y=9

2y= 12
divide it by 2

y= 6


put y in any equation

5x-2 (6)=3

5x-12=3
5x= 3+12=15
divide by 5
x=3

y= 6
3 0
3 years ago
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Answer 9
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3 0
2 years ago
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Can someone please help I will give u brainliest
kotegsom [21]

Answer:

it's 24.5 Sq feet

Step-by-step explanation:

if you multiply 7 × 3.5 you get the awnser

6 0
2 years ago
Read 2 more answers
How do you do this question?
alina1380 [7]

Answer:

(8√2) / 15

Step-by-step explanation:

A curve bounded by the y-axis is represented by in terms of dy;

\int \:x\:dt

When the curve crosses the y-axis, x will be 0. In this case x is the function of t, so we have to solve for x(t) = 0;

0 = t^2 + 2t --- (1)

Solution(s) => t = 0, t = 2

dy = (1/2 * 1/√t)dt --- (2)

Our solutions (0, 2) are our limits. The area of the curve is in the form A\:=\:\int _b^a\:f\left(t\right)g'\left(t\right)dt , so now let's introduce the limits of integration, x(t) and dy/dt. Remember, dy/dt = (1/2 * 1/√t) (second equation). 1/2 * 1/√t can be rewritten as 1/2 * t^(-1/2)....

A\:=\:\int _2^0\:\left(t^2-2t\right)\left(\frac{1}{2}t^{-\frac{1}{2}}\right)dt\\\\= \int _2^0\:\left(\frac{1}{2}t^{\frac{3}{2}}-t^{\frac{1}{2}}\right)dt\\\\= \left[\frac{t^{\frac{5}{2}}}{5}-\frac{2t^{\frac{3}{2}}}{3}\right]_2^0\\\\= 0\:-\:\left(\frac{4\sqrt{2}}{5}-\frac{4\sqrt{2}}{3}\right)\\\\= \frac{8\sqrt{2}}{15}

Your solution is 8√2 / 15

7 0
2 years ago
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