Answer:
- the speed of a person "stuck" to the wall is 14.8 m/s
- the normal force of the wall on a rider of m=54kg is 1851 N
- the minimum coefficient of friction needed between the wall and the person is 0.29
Explanation:
Given information:
the radius of the cylindrical room, R = 6.4 m
the room spin with frequency, ω = 22.1 rev/minutes = 22.1
= 2.31 rad/s
mass of rider, m = 54 kg
the speed of a person "stuck" to the wall
v = ω R
= 2.31 x 6.4
= 14.8 m/s
the normal force of the wall on a rider
F = m a
a = ω^2 R
=
R
= 
F = 
= 
= 1851 N
the minimum coefficient of friction needed between the wall and the person
F(friction) = μ N
W = μ N
m g = μ 
g = μ
μ = 
= 
= 0.29
Answer:
A pendulum works by converting energy back and forth, a bit like a rollercoaster ride. When the bob is highest (furthest from the ground), it has maximum stored energy (potential energy). ... So as the bob swings (oscillates) back and forth, it repeatedly switches its energy back and forth between potential and kinetic.
<span>The formulas are,
Impulse = mv-mu ....... (1)
v^2 = u^2 + 2as .......... (2)
We know that,
u=0
a=acceleration=gravity = 9.80665 m/s^2 = 9.81 m/s^2
s=19.6
sub (2) we get,
v^2 = 0+ 2*9.81*19.6
v^2 = 2*9.81*19.6
v^2 = 384.552
v = 19.6099
v = 19.61 m/s
Sub v=19.61 m/s in (1) we get,
Impulse = mv - mu
we know that u=0; v= 19.61 m/s; m= 3.00 kg
Impulse = 3(19.61) - 3(0)
Impulse = 58.83-0
Impulse = 58.83 Ns.
Therefore the gravitational force exerted by the stone is 58.83 Ns.</span>