All categories

3 years ago

The difference between a red shift and a blue shift has to do with wavelength frequency. T or F

Physics

1 answer:

ale4655 [162]3 years ago

5 0

Answer:

Its True

Explanation:

The difference between a red shift and a blue shift is as follows;

Red shift: In the red shift, light changes as the object in space (such as star or galaxies) moves away from us then the light is shifted to red end.The light is shifted to a shorter frequency. In this case, the light is shifted to a longer wavelength.

You might be interested in

What if the store decided to arrange their items according to size, color or shape? What do you think will happen to your shoppi

Y_Kistochka [10]

Answer: it will change dramatically

Explanation:

8 0

3 years ago

A long, thin superconducting wire carrying a 17 A current passes through the center of a thin, 3.0-cm-diameter ring. A uniform e

nalin [4]

Answer:

$\frac{dE}{dt} =- 2.72 *10^{15} \ N/C \cdot s$

The direction of the electric field is opposite that of the current

Explanation:

From the question we are told that

The current is $I = 17\ A$

The diameter of the ring is $d = 3.0 \ cm = 0.03 \ m$

Generally the radius is mathematically represented as

$r = \frac{d}{2}$

$r = \frac{0.03}{2}$

$r = 0.015 \ m$

The cross-sectional area is mathematically represented as

$A = \pi r^2$

=> $A = 3.142 * (0.015^2)$

=> $A = 7.07 *10^{-4 } \ m^ 2$

Generally according to ampere -Maxwell equation we have that

$\oint \= B \cdot \= ds = \mu_o I + \epsilon_o \mu _o\frac{ d \phi }{dt }$

Now given that $\= B = 0$ it implies that

$\oint \= B \cdot \= ds = 0$

$\mu_o I + \epsilon_o \mu _o\frac{ d \phi }{dt } = 0$

Where $\epsilon _o$ is the permittivity of free space with value $\epsilon_o = 8.85*10^{-12 } \ m^{-3} \cdot kg^{-1}\cdot s^4 \cdot A^2$

$\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} N/A^2$

$\phi$ is magnetic flux which is mathematically represented as

$\phi = E * A$

Where E is the electric field strength

$\mu_o I + \epsilon_o \mu _o \frac{ d [EA] }{dt } = 0$

=> $\frac{dE}{dt} =- \frac{I}{\epsilon_o * A }$

=> $\frac{dE}{dt} =- \frac{17}{8.85*10^{-12} * 7.07*10^{-4} }$

=> $\frac{dE}{dt} =- 2.72 *10^{15} \ N/C \cdot s$

The negative sign shows that the direction of the electric field is opposite that of the current

8 0

3 years ago

What is the force that acts on an object and opposes its motion called?

Alika [10]

Friction is the force that acts on an object and opposes its motion

5 0

3 years ago

When two trains, going in opposite directions, are passing on tracks that are laid out close together, the train cars can often

Afina-wow [57]

<h3>Answer:</h3>

"<u>Therefore, the speed of the air decreases, the pressure acting on the two trains increases (by Bernoulli's principle), and the two trains lean in toward one another</u>."

6 0

3 years ago

Read 2 more answers

A ball is dropped from the top of a building that is known to be 400 feet high. The formula for finding the height of the ball a

Ira Lisetskai [31]

Answer:

3 seconds

Explanation:

Height of the building = 400 feet

Height of the ball from the ground is given by

h=400−16t²

This formula has been derived from

$s=ut+\frac{1}{2}at^2$

a = Acceleration due to gravity = 32 ft/s²

u = Initial velocity = 0

t = Time taken

Substituting all the values we get

$s=0t+\frac{1}{2}32t^2\\\Rightarrow s=16t^2$

This is the height of the ball from the top of the building

The height of the ball from the ground will be

h = 400-s

⇒h = 400−16t²

When h = 256 ft

$256=400-16t^2\\\Rightarrow t=\sqrt{\frac{256-400}{-16}}\\\Rightarrow t=3\ s$

Time taken by the ball to reach a height of 256 feet above the ground is 3 seconds

4 0

4 years ago