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geniusboy [140]

2 years ago

5

A softball is fouled off with a vertical velocity of 20 m/s and a horizontal velocity of 15 m/s. what is the resultant velocity

of the ball

1 answer:

Kruka [31]2 years ago

6 0

25 m/s is the answer

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2. What is the total effect of sound produced in an enclosed space called?

Igoryamba

I believe it is Acoustics, the real name for it would be like Reverberation. But go with Acoustics. :)

6 0

2 years ago

Loud of dust and gas in space is a(n) Blank Space __________.

madreJ [45]

A cloud in space that is composed of dust and gas is call a nebula. The word "nebula" is derived from the Latin word for "cloud," and nebulae in space are indeed large interstellar clouds made up of dust, hydrogen, helium and plasma.

6 0

2 years ago

Read 2 more answers

On Earth, 1 kg = 9.8 N = 2.2 lbs. On the Moon, 1 kg = 1.6 N = 0.37 lbs. Use these relationships to answer the following question

romanna [79]

Answer:

(a) 490 N on earth

(b) 80 N on earth

(c) 45.4545 kg on earth

(d) 270.27 kg on moon

Explanation:

We have given 1 kg = 9.8 N = 2.2 lbs on earth

And 1 kg = 1.6 N = 0.37 lbs on moon

(a) We have given mass of the person m = 50 kg

As it is given that 1 kg = 9.8 N

So 50 kg = 50×9.8 =490 N

(b) Mass of the person on moon = 50 kg

As it is given that on moon 1 kg = 1.6 N

So 50 kg = 50×1.6 = 80 N

(c) We have given that weight of the person on the earth = 100 lbs

As it is given that 1 kg = 2.2 lbs on earth

So 100 lbs = 45.4545 kg

(d) We have given weight of the person on moon = 100 lbs

As it is given that 1 kg = 0.37 lbs

So 100 lbs $\frac{100}{0.37}=270.27kg$

8 0

3 years ago

A rocket burns fuel as it shoots into the sky. What happens to the mass and volume of the rocket?

diamong [38]

Answer:

mass goes down volume remains the same

6 0

2 years ago

A truck starts off 151 miles directly north from the city of Hartville. It travels due east at a speed of 41 miles per hour. Aft

Bess [88]

Answer:

9.51

Explanation:

The distance s is given by:

$s(t) = \sqrt{151^2 + (vt)^2}$

The change in distance is given by the time derivative of s:

$\frac{ds}{dt} = \frac{v^2t}{\sqrt{151^2 + (vt)^2}}$

For the time t you solve the equation of distance x for time:

$x = vt => t = \frac{x}{v}$

Plugging in for t:

$\frac{ds}{dt}(t=\frac{x}{v})=\frac{vx }{\sqrt{151^2 + x^2}}=9.51$

6 0

2 years ago