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geniusboy [140]

3 years ago

5

A softball is fouled off with a vertical velocity of 20 m/s and a horizontal velocity of 15 m/s. what is the resultant velocity

of the ball

1 answer:

Kruka [31]3 years ago

6 0

25 m/s is the answer

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A circular rod has a radius of curvature R = 9.09 cm and a uniformly distributed positive charge Q = 6.49 pC and subtends an ang

Digiron [165]

Answer:

E = 1.19 N/C

Explanation:

Let's first determine the length of the arc which can be given as:

L= Rθ

where:

L = length of the arc

R = radius of curvature

θ = angle in radius

L = (9.09×10⁻²m)(2.59)

L = (0.0909)(2.59)

L = 0.235431 m

Then, the magnitude of electric field that Q produces at the center of curvature can be calculated by using the formula:

$E= \frac{\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}-sin(-\frac{\theta}{2})]$

$E= \frac{\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}+sin(\frac{\theta}{2})]$

$E= \frac{2\lambda}{4 \pi E_oR}[sin\frac{\theta}{2}]$

Since $\lambda = \frac{Q}{L}$

where;

L = length

Q = charge

λ = density of the charge;

then substituting $\frac{Q}{L}$ for λ, we have :

$E= \frac{2(\frac{Q}{L})}{4 \pi E_oR}[sin\frac{\theta}{2}]$

$E= \frac{2Q[sin\frac{\theta}{2}]}{4 \pi E_oLR}$

substituting our given parameter; we have:

$E= \frac{2(6.26*10^{-12}C)[sin\frac{2.59rad}{2}]}{4 \pi (8.85*10^{-12}C^2/N.m^2)(0.235431)(0.0909)}$

E = 1.1889 N/C

E = 1.19 N/C

∴ the magnitude of the electric field that Q produces at the center of curvature = 1.19 N/C

4 0

3 years ago

The half life of carbon-14 is 5730 years. How old is a bone if it presently contains 0.3125 g of carbon-14, but it was estimated

TiliK225 [7]

The age of the bone is 45840 years.

We'll begin by calculating the number of half-lives that has elapsed.

Amount remaining (N) = 0.3125 g

Initial amount (N₀) = 80 g

<h3>Number of half-lives (n) =? </h3>

N × 2ⁿ = N₀

0.3125 × 2ⁿ = 80

Divide both side by 0.3125

2ⁿ = 80 / 0.3125

2ⁿ = 256

2ⁿ = 2⁸

<h3>n = 8</h3>

Thus, 8 half-lives has elapsed

Finally, we shall determine the age of the bone.

Half-life (t½) = 5730 years

Number of half-lives (n) = 8

<h3>Time (t) =? </h3>

t = n × t½

t = 8 × 5730

<h3>t = 45840 years </h3>

Therefore, the age of the bone is 45840 years.

Learn more on half-life: brainly.com/question/15900105

5 0

3 years ago

Immediately following the arrival of the stimulus at a skeletal muscle cell there is a short period called the ________ period d

Naddika [18.5K]

Answer:

Latent period.

Explanation:

Immediately following the arrival of the stimulus at a skeletal muscle cell there is a short period called the Latent period during which the events of excitation-contraction coupling occur.

The period of incubation, the interval preceding exposure to a pathogen, toxin or radiation, and when effects occur. Muscle contracting, the time between a nerve stimulus, and muscle contraction.

5 0

3 years ago

Electromagnetic waves propagate much differently in conductors than they do in dielectrics or in vacuum. If the resistivity of t

evablogger [386]

Answer:

Del(ρ/ε₀) - (Del)²E = -dμ₀J/dt

Explanation:

From Maxwell's fourth equation

Curl B = μ₀J + μ₀ε₀dE/dt (1) where the second term is the displacement current.

If the oscillation conduction current in the conductor is much larger than the displacement current then, the displacement current goes to zero. So we have

Curl B = μ₀J (2)(since μ₀ε₀dE/dt = 0)

From maxwell's third equation

Curl E = -dB/dt (3)

taking curl of the above from the left

Curl(Curl E) = Curl(-dB/dt)

Curl(Curl E) = (-d(CurlB)/dt) (4)

Substituting for Curl B into (4), we have

Curl(Curl E) = -dμ₀J/dt

Del(DivE) - (Del)²E = -dμ₀J/dt (5)

From Maxwell's first equation,

DivE = ρ/ε₀

Substituting this into (5), we have

Del(ρ/ε₀) - (Del)²E = -dμ₀J/dt

4 0

3 years ago

The sky is blue because: Select one: a. the index of refraction for air is slightly larger for blue than for red b. atomic hydro

lapo4ka [179]

Answer:

a. the index of refraction for air is slightly larger for blue than for red

5 0

3 years ago