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Fofino [41]
3 years ago
15

HELP PLEASE. ALGEBRA.

Mathematics
2 answers:
serg [7]3 years ago
6 0
the answer is a because the +2 is the why intercept.
Kryger [21]3 years ago
3 0

Answer:

A

Step-by-step explanation:

For this question, just look at the y-intercept (equals 2 btw), that is where the line crosses the y-axis. Hope this helps :)

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Second derivative test for:<br> y= e^x (x^2 -7x +13)
garik1379 [7]
First derivative is e^x(x^2-7x+13)+e^x(2x-7)
Which can be simplified to e^x(x^2-7x+13+2x-7)
Second derivative is e^x(x^2-5x+6)+e^x(2x-5)
Which then can be simplified to e^x(x^2-3x+1)
4 0
3 years ago
Megan earned $48 working 5 hours Friday afternoon. She has plans to work 3 more hours Saturday morning. Consider this proportion
mestny [16]
Idk maybe read it again to understan better i just want to have 20 characters to complete this answer k bye
4 0
3 years ago
Read 2 more answers
I need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)
Dahasolnce [82]

Five number summary and IQR of both the data sets are different.

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Part A:

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set into four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

The interquartile range of the data is

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =16-6.2\\     =9.5

The interquartile range of the data is

IQR=Q_3-Q_1\\     =Q_3-Q_1\\     =15.5-8\\     =7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.

To learn more about the symmetric visit:

brainly.com/question/1002723

#SPJ1

6 0
2 years ago
The manager at a sports radio station will be covering several football games over the weekend. She knows that most of her liste
Paraphin [41]

Complete Question:

The manager at a sports radio station will be covering several football games over the weekend. She knows that most of her listeners are at least 22 years old and wants to know what age group she should gear her advertisements to for the games. She takes a random sample of 46 listeners from age 22-39 and 57 listeners who are 40 and older and asks them if they are likely to tune in to football games. The "yes" responses are recorded in the file attached below.

1. At the 0.05 level of significance, is there a significant difference in the proportion of listeners based on age?

2. Is there evidence to suggest that there is a significant difference in the proportion of listeners based on age?

Answer:

1) There is no significant difference in the proportion of listeners based on age

2) No, there is no evidence

Step-by-step explanation:

Sample size of group 1, n_1 = 46

Sample size of group 2, n_2 = 57

Number of Yes in group 1,  X_1 = 32

Number of Yes in group 2, X_2 = 47

Proportion of Yes in group 1:

\hat{p_1} = \frac{X_1}{n_1} \\\hat{p_1} = \frac{32}{46}\\\hat{p_1} = 0.6957

Proportion of Yes in group 2:

\hat{p_2} = \frac{X_2}{n_2} \\\hat{p_2} = \frac{47}{57}\\\hat{p_2} = 0.8246

Null Hypothesis, H_0: p_1 = p_2

Alternate Hypothesis,H_a: p_1 \neq p_2

\hat{p} = \frac{X_1 + X_2}{n_1 + n_2}  \\\\\hat{p} = \frac{ 32+47}{46+57} \\\\\hat{p}= 0.767

Significance level,

Calculate the test statistic

z = (\hat{p_1} - \hat{p_2})/\sqrt{(\hat{p} * (1-\hat{p}) * (\frac{1}{N_1}  + \frac{1}{N_2})}\\\\z = (0.6957-0.8246)/ \sqrt{(0.767*(1-0.767)*(1/46 + 1/57))}\\\\z = -1.54

Get the P-value from the probability distribution table:

At z = -1.54, P-value = 0.1236

Since (P-value = 0.1236) > (α = 0.05), we will accept the null hypothesis. This means that there is no evidence to suggest that there is difference in the proportion of listeners based on age.

7 0
2 years ago
3 movie tickets cost $48. At this rate, what is the cost of 15 movie tickets
Snowcat [4.5K]

Answer:

The total of the 15 tickets would be $240

Step-by-step explanation:

If you divide 48 and 3 you get 16 which is the cost for each ticket and then yuo multiply 16 by 15 and you get 240

3 0
3 years ago
Read 2 more answers
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