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2 years ago

Figure ABCD is a parallelogram.

Mathematics

2 answers:

fiasKO [112]2 years ago

8 0

Answer:

I think it's the second

Step-by-step explanation:

Eddi Din [679]2 years ago

3 0

Answer:

stack AD with bar on top space text is parallel to end text BC with bar on top.

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To factor a<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class="la

Ivan

Answer:

I'm not sure. Try asking <u>Goo</u>g<u>le</u>.

Plzzzzz give me Brainliest!!!!!

4 0

2 years ago

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Please help me solve question 2

sergiy2304 [10]

Answer:

solution: ( 3 , 6 )

$\sf y =6$

$\sf x =3$

Step-by-step explanation:

$\sf y = \frac{2}{3} x+4$

$\sf 2x+3y = 24$

make y the subject in equation 2:

$\sf 2x+3y = 24$

$\sf 3y = 24-2x$

$\sf y = \frac{24-2x}{3}$

insert this in equation 1:

$\sf \frac{24-2x}{3} =\frac{2}{3} x+4$

$\sf \sf \frac{24-2x}{3} =\frac{2x+12}{3}$

$\sf (24-2x) = (2x+12)$

$\sf -2x-2x=12-24$

$\sf -4x=-12$

$\sf x =3$

solve for y:

$\sf y = \frac{24-2x}{3}$

$\sf y = \frac{24-2(3)}{3}$

$\sf y =6$

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2 years ago

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Solve for x in the following problem Remember to align your variables.

choli [55]

Answer:

X=11

Step-by-step explanation:

X=11 because u Solve for the first variable in one of the equations, then substitute the result into the other equation.

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2 years ago

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laiz [17]

what is the question pls.

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3 years ago

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Prove that the following four points will form a rectangle when connected in order

Lemur [1.5K]

Answer:

Step-by-step explanation:

If the diagonals of the rectangle are congruent,

AC = BD

By using formula to calculate the distance between two points,

Distance between two points = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A(0, -3) and C(2, 8),

AC = $\sqrt{(8+3)^2+(2-0)^2}$

= $\sqrt{125}$

= $5\sqrt{5}$

Similarly, distance between two points B(-4, 0) and D(6, 5),

BD = $\sqrt{(5-0)^2+(6+4)^2}$

= $\sqrt{125}$

= $5\sqrt{5}$

Therefore, both the diagonals are congruent.

Hence, given quadrilateral ABCD is a rectangle.

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2 years ago