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enyata [817]
2 years ago
10

Find the standard deviation for the set of data. (17,26,28,9,30, 29,6,21,23}​

Mathematics
1 answer:
gogolik [260]2 years ago
7 0

Using it's concept, the standard deviation for the given data-set is of 8.22.

<h3>What are the mean and the standard deviation of a data-set?</h3>

  • The mean of a data-set is given by the <u>sum of all values in the data-set, divided by the number of values</u>.
  • The standard deviation of a data-set is given by the square root of the <u>sum of the differences squared between each observation and the mean, divided by the number of values</u>.

The mean for this problem is:

M = (17 + 26 + 28 + 9 + 30 + 29 + 6 + 21 + 23)/9 = 21

Hence the standard deviation is:

S = \sqrt{\frac{(17-21)^2 + (26-21)^2 + (28-21)^2 + \cdots + (21-21)^2 + (23-21)^2}{9}} = 8.22

More can be learned about the standard deviation of a data-set at brainly.com/question/12180602

#SPJ1

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What is the volume of a cone that has a height of 7 mm and a radius of 3 mm? Use 3.14 to approximate pi and round the answer to
Anna [14]
Volume=1/3 times area of base (circle) times height

circle=3.14 times radius^2
circle=3^2 times 3.14
circle=9 times 3.14=28.26
times height (7)
197.82
times 1/3=65.94
answer is 65.94 mm^3
3 0
3 years ago
Find Sn for the arithmetic series 5+7+9 + … and determine the value of n for which the series has sum 165.
SVETLANKA909090 [29]

Answer:

see explanation

Step-by-step explanation:

the sum to n terms of an arithmetic sequence is

S_{n} = \frac{n}{2}[2a + (n - 1)d ]

where d is the common difference and a is the first term

here d = 9 - 7 = 7 - 5 = 2 and a = 5, hence

S_{n} = \frac{n}{2}[(2 × 5) + 2(n - 1) ]

                        = \frac{n}{2}(10 + 2n - 2)

                        = \frac{n}{2}(2n + 8)

                        = n² + 4n

When sum = 165, then

n² + 4n = 165 ← rearrange into standard form

n² + 4n - 165 = 0 ← in standard form

(n + 15)(n - 11) = 0 ← in factored form

equate each factor to zero and solve for n

n + 15 = 0 ⇒ n = - 15

n - 11 = 0 ⇒ n = 11

but n > 0 ⇒ n = 11



4 0
3 years ago
Do anyone know the answer
Vlada [557]

Answer:

A

Step-by-step explanation:

Domain the "input" to the function, range is the "output" of the function.

6 0
2 years ago
Read 2 more answers
A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of
Gwar [14]

\bold{\huge{\underline{ Solution}}}

<h3><u>Given </u><u>:</u><u>-</u></h3>

  • A marker in the center of the fairway is 150 yards away from the centre of the green
  • While standing on the marker and facing the green, the golfer turns 100° towards his ball
  • Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

  • Distance between marker and centre of green is 150 yards
  • <u>That </u><u>is</u><u>, </u>Height = 150 yards
  • For facing the green , The golfer turns 100° towards his ball
  • <u>That </u><u>is</u><u>, </u>Angle = 100°
  • The golfer peces off 30 yards to his ball
  • <u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}

  • Here, a = perpendicular height
  • b = base
  • c = hypotenuse
  • cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}

\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}

\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}

\sf{ x^{2} = 22500 + 900 + 156.6}

\sf{ x^{2} = 23556.6}

\bold{ x = 153.48\: yards }

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0
2 years ago
The product of five and a number plus 10 is at least thirty
inna [77]

Answer: Greater of equal sign

Step-by-step explanation:

5+10+x is greater than or equal to 30 ( use the greater of equal to sign)

7 0
3 years ago
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