2.94
×
10
24
⋅
molecules
6.022
×
10
23
⋅
molecules
⋅
mol
−
1
×
142.3
⋅
g
⋅
mol
−
1
≅
700
⋅
g
Determine the mass of each of the following amounts. a. 1.366 mol of
NH3
, b. 0.120 mol of glucose,
C6H12O6
, c. 6.94 mol barium chloride,
BaCl2
, d. 0.005 mol of propane,
C3H8
Answer:
156.86 g / mol
Explanation:
We start from the molarity law
Cm = n / V
n = w / M
then
Cm = (w / M) / V
Cm = w / (M × V)
where:
Cm is the molarity
n number of moles
w a mass of the solute
M is the molar mass of the solute (which is needed)
V the volume of the solution in liters
Then the M can be calculated as following:
M = w / (Cm × V)
M = 100 / (0.75 × 0.85) = 156.86 g / mol
Answer: D:wavelenght
Explanation: Students will understand that shorter wavelengths have higher frequency and energy.
Answer:
D -35 West
if this is correct plz mark me brainliest because this is my first question