Answer:
3 × 10¹⁰⁹
Explanation:
2Cr (s) → 2Cr³⁺ + 6e⁻
and,
Ec° for the above reaction = 0.74 V
also,
3Cu²⁺ (aq) + 6e⁻ → 3Cu(s)
and,
Ea° for the above reaction = 0.34 V
Now,
The cell potential, E° = 0.34 + 0.74 = 1.08
E° = 
thus,
0.34 = 
here, n is the number of electrons exchanged
n = 6
1.08 = 
or
㏒ k = 109.44
taking anti-log both sides
we get
k = 3 × 10¹⁰⁹
Hence, the answer is option (A) 3 × 10¹⁰⁹
Answer:
lowest to Highest
Carbon atom
Methane molecule (CH4)
Graphite
Diamond
Explanation:
A carbon atom would be the lowest complexity on this list, that is because it is a lone molecule with no other bonding between other atoms. The same forces interacting between the carbon atom would be the same for the others.
Next would be methane. Methane is a hydrocarbon composed of a single carbon atom bonded covalently with four hydrogens. The electrons within the hydrogen atoms repel each other causing them to be dispersed around the carbon atom to form a
tetrahedral shape. While more complex, the other two are continuous structures made from carbon atoms bonded to gather to form crystal structures.
Graphite is considered to be a crystal structure, just like a diamond. However, the biggest difference between them is their atomic and crystal frameworks. Diamonds have a rigid 3-dimensional structure whilst graphite is composed of 2d planes of graphite with carbon-carbon double bonds connecting the layers. Due to this, a diamond would be more complex then grpahite
Answer:
Color change, Temprature change, Odor change, Effervescence (Bubbles)
Explanation:
See the sketch attached.
<h3>Explanation</h3>
The Lewis structure of a molecule describes
- the number of bonds it has,
- the source of electrons in each bond, and
- the position of any lone pairs of electrons.
Atoms are most stable when they have eight or no electrons in their valence shell (or two, in case of hydrogen.)
- Each oxygen atom contains six valence electrons. It demands <em>two</em> extra electrons to be chemically stable.
- Each sulfur atom contains six valence electrons. It demands <em>two </em> extra electrons to be chemically stable.
- Each hydrogen atom demands <em>one</em> extra electron to be stable.
H₂O contains two hydrogen atoms and one oxygen atom. It would take an extra 2 + 2 × 1 = 4 electrons for all its three atoms are stable. Atoms in an H₂O would achieve that need by sharing electrons. It would form a total of 4 / 2 = 2 O-H bonds.
Each O-H bond contains one electron from oxygen and one from hydrogen. Hydrogen has no electron left. Oxygen has six electrons. Two of them have went to the two O-H bonds. The remaining four become 4 / 2 = 2 lone pairs. The lone pairs repel the O-H bonds. By convention, they are placed on top of the two H atoms.
Similarly, atoms in a SO₂ molecule demands an extra 2 × 2 + 2 = 6 electrons for its three atoms to become chemically stable. It would form 6 / 2 = 3 chemical bonds. Loops are unlikely in molecules without carbon. As a result, one of the two O atoms would form two bonds with the S atom while the other form only one.
Atoms are unstable with an odd number of valence electrons. The S atom in SO₂ would have become unstable if it contribute one electron to each of the three bond. It would end up with 3 × 2 + 3 = 9 valence electrons. One possible solution is that it contributes two electrons in one particular bond. One of the three bonds would be a coordinate covalent bond, with both electrons in that bond from the S atom. In some textbooks this type of bonds are also known as dative bonds.
Dots and crosses denotes the origin of electrons in a bond. Use the same symbol for electrons from the same atom. Electrons from the oxygen atoms O are shown in blue in the sketch. They don't have to be colored.