The correct answer is option B. The most dense phase of matter is the solid phase and the least dense are gases. However, there is an exception. Water is the exception. Solid water or ice is less dense than the liquid phase therefore it floats on liquid water.
Answer:
[Top row] - Chemical bonds
[2nd Row L-R] - Force, Ionic, Covalent
[3rd Row L-R] - Atoms, Lost or Gained, Shared
[4th Row L-R] - More stable, Metal and Nonmetal, Nonmetal and Nonmetal
Explanation:
<u>Chemical bonds</u> are a<u> </u><u>force</u> that hold together <u>atoms</u> in a substance to make compounds <u>more stable.</u>
<u>Chemical bonds</u> include two kinds: <u>Ionic</u> and <u>Covalent.</u>
<u>Ionic</u> in which electrons are <u>lost or gained</u> where attraction is between a <u>Metal and Nonmetal.</u>
<u>Covalent</u> in which electrons are shared where attraction is between a <u>nonmetal and nonmetal</u>.
I have been able to fill the concept map using the correct terms or phrases. The concept map talks about chemical bonds. There are two types of chemical bonds; which ionic bond and covalent bond.
We can use two equations for this problem.<span>
t1/2 = ln
2 / λ = 0.693 / λ
Where t1/2 is the half-life of the element and λ is
decay constant.
20 days = 0.693 / λ
λ = 0.693 / 20 days
(1)
Nt = Nο eΛ(-λt) (2)
Where Nt is atoms at t time, No is the initial amount of substance, λ is decay constant and t is the time
taken.
t = 40 days</span>
<span>No = 200 g
From (1) and (2),
Nt = 200 g eΛ(-(0.693 / 20 days) 40 days)
<span>Nt = 50.01 g</span></span><span>
</span>Hence, 50.01 grams of isotope will remain after 40 days.
<span>
</span>
The given concentration of boric acid = 0.0500 M
Required volume of the solution = 2 L
Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.
Calculating the moles of 0.0500 M boric acid present in 2 L solution:

Converting moles of boric acid to mass:

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.