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3 years ago

Pleaseeee help me....Use the Law of Sines to solve the triangle. Round your answers to two decimal places.

Mathematics

1 answer:

alexira [117]3 years ago

7 0

Answer:

a = 1.11
B = 105.4°
c = 2.95

Step-by-step explanation:

B = 180 -A -C = 105.4 . . . . sum of angles in a triangle is 180°

The missing side lengths can be found from the Law of Sines:

a/sin(A) = c/sin(C)

a = c·sin(A)/sin(C) = 2.46·sin(21.2°)/sin(53.4°) ≈ 1.11

Likewise, ...

b = c·sin(B)/sin(C) = 2.46·sin(105.4°)/sin(53.4°) ≈ 2.95

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68% of the tickets sold at a water park were child tickets. If the park sold 50 tickets in all, how many child tickets did it se

Mnenie [13.5K]

Answer:

$\boxed{\bf\: The \: park \: sold \boxed{ 34{}} \: child \: tickets.}$

Step-by-step explanation:

Given:

Percentage of Tickets sold at a water park - 68%

The Number of Tickets if the park sold in all - 50

To Find:

The Number of child tickets the park sold.

Solution:

We know that 68% equals to 68/100.

Step 1: Multiply 68/100 by 50 which is the number of tickets the park sold :-

$\sf \: = \: \cfrac{68}{100} \times 50$

Note:The Simplified form of 68/100 * 50 would be the answer to this question.

Step 2: Cancel One zero of 50 and one zero of 100,That is:-

$\sf = \cfrac{68}{ 10\cancel0} \times 5 \cancel0$

Results to,

$\sf = \cfrac{68}{10} \times 5$

Step 3: Cancel 5 and 10, That is:-

$\sf = \cfrac{68}{ \cancel{10 }} \times \cancel5$

Results to,

$\sf =\: \cfrac{68}{2} \times 1$

$\sf = \cfrac{68}{2}$

Step 4: Cancel 68 and 2, That is:-

$\sf =\: \cfrac{ \cancel{68}}{ \cancel2}$

Results to,

$\sf = \cfrac{34}{1}$

$\sf = 34$

34 is the result.

Hence,

$\underline{ \rm \: The \: park \: sold \: \bold{ 34 } \: child \: tickets.}$

________________________________

I hope this helps!

Let me know if you have any questions.I am joyous to help!

6 0

3 years ago

Elizabeth continued to save for her car down payment.

Reil [10]

ummmm it could be third one i guesss

6 0

3 years ago

Read 2 more answers

Which choice is the explicit formula for the following geometric sequence?0.5, -0.1, 0.02, -0.004, 0.0008, ...

Minchanka [31]

$a_1=0.5\\a_2=-0.1\\a_3=0.02\\a_4=-0.004\\a_5=0.0008\\\\a_n=a_1\cdot q^{n-1}\\\\q=a_2:a_1\to q=-0.1:0.5=-0.2\\\\a_n=0.5\cdot(-0.2)^{n-1}=0.5\cdot(-0,2)^n\cdot(-0.2)^{-1}\\\\=0.5\cdot(-0.2)^n\cdot(-5)=-2.5\cdot(-0.2)^n\\\\\boxed{a_n=-2.5\cdot(-0.2)^n}$