Pleaseeee help me....Use the Law of Sines to solve the triangle. Round your answers to two decimal places.
1 answer:
Answer:
- a = 1.11
- B = 105.4°
- c = 2.95
Step-by-step explanation:
B = 180 -A -C = 105.4 . . . . sum of angles in a triangle is 180°
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The missing side lengths can be found from the Law of Sines:
a/sin(A) = c/sin(C)
a = c·sin(A)/sin(C) = 2.46·sin(21.2°)/sin(53.4°) ≈ 1.11
Likewise, ...
b = c·sin(B)/sin(C) = 2.46·sin(105.4°)/sin(53.4°) ≈ 2.95
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Given:
The width at the base of parabolic tunnel is 7 m.
The ceiling 3 m from each end of the base there are light fixtures.
The height to light fixtures is 4 m.
To find:
Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.
Solution:
The width at the base of tunnel is 7 m.
Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.
The function of height is:
...(i)
Where, a is a constant.
The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).
Putting x=3 and h(x)=4 in (i), we get
Putting , we get
...(ii)
The center of the parabola is the midpoint of 0 and 7, i.e., 3.
The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.
2 m on the left side of the center is x=1.5.
A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.
Putting x=1.5 in (ii), we get
Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.
