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never [62]
3 years ago
9

The point (5,4) lies on a circle. what is the length of the radius of this circle if the center is located at (3,2)

Mathematics
1 answer:
Art [367]3 years ago
4 0
Use the x and y values from your point and the h and k from the center to write the equation you need to solve for r.  The general form of the equation for a circle is (x-h) ^{2} +(y-k) ^{2} = r^{2}.  We will fill in accordingly: (5-3) ^{2}+(4-2) ^{2} = r^{2}.  Solve for r to get that r= \sqrt{8}
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-4(5k-7)-2k=-2(9k+5)
Mice21 [21]
If you distribute -4 through (5k-7), it equals -20k + 28. Then put on the other -2k on that side of the equals sign and you should have -22k + 28 = -2(9k+5) Then you need to distribute -2 through (9k+5) which equals -18k - 10. You then should have -22k+28=-18k-10. Add 22k to both sides to cancel it out, then you should have 28=4k-10. Add 10 to both sides to get the 4k by itself, which will be 38=4k, then divide both sides by 4 to get k by itself. 38/4 = 19/2. k = 19/2
5 0
3 years ago
claudias filing status on last years tax return was single, while Angelos was head of household. If both had taxable incomes of
Ainat [17]

1378 more than angelo

3 0
3 years ago
Read 2 more answers
OK PLEASE HELP ME GUYS I ALWAYS HELP YOU so here it is
gtnhenbr [62]
F=P(1/2)^(t/h)
F=future amount
P=present amount
t=time elapsed
h=legnth of half life

P=96
t=2
h=1
F=96(1/2)^(2/1)
F=96(1/2)^2
F=96(1/4)
F=96/4
F=24 grams



grow by 35%
compound interest
F=P(1+rate)^time
F=95000(1+0.35)^10
F=95000(1.35)^10
F=95000(20.106555868618)
F=1910122.9075187  
8 0
3 years ago
A sphere has a radius of 1.5 inches.
Schach [20]
V = (4/3)×3.14×(1.5^3)
V = 14.1 in^3
7 0
3 years ago
Is rolling a 3 standard doe and then rolling a sum greater than 4 when counting the next roll an independent event?
zhannawk [14.2K]

Answer:

False

Step-by-step explanation:

In this question, you roll 3 from the standard die and then add it with the next roll to see if the sums are greater than 4.

From this explanation you can see that you use the result from your first roll for the second event, so we can conclude that the event is dependent.  

Imagine if we change the result of the first roll into 5, without adding the second roll we can know that the sum will be greater than 4. The first event result will influence the second event, so it is a dependent event.

5 0
3 years ago
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