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3 years ago

The point (5,4) lies on a circle. what is the length of the radius of this circle if the center is located at (3,2)

1 answer:

4 0

Use the x and y values from your point and the h and k from the center to write the equation you need to solve for r. The general form of the equation for a circle is $(x-h) ^{2} +(y-k) ^{2} = r^{2}$ . We will fill in accordingly: $(5-3) ^{2}+(4-2) ^{2} = r^{2}$ . Solve for r to get that $r= \sqrt{8}$

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Assume the mean life of an iPhone is 5 years (60 months)and a standard deviation of 8 months If the age in years at which an iPh

melamori03 [73]

Answer:

Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=

................ii

form i and ii we can write

v^2= \frac{1}{2} u^2v

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

8 0

2 years ago

A rectangular prism has a length of 4x inches, a width of 3x inches, and a height of 5x inches. if the prism has a volume of 20,

lbvjy [14]

I hope this helps you

7 0

4 years ago

5+(−3)−6<br><br> When safari says it’s restricted qwq

Luba_88 [7]

Answer:

5+(-3)-6

= 5+(-9)

= -4

Step-by-step explanation:

Hope it helps..

7 0

3 years ago

Read 2 more answers

George invited 65 students in his school to volunteer at a charity race. 39 of the students signed up to volunteer. What percent

mr Goodwill [35]

Answer:

60%

Step-by-step explanation:

Divide the amount of people who showed up by the total invited...

39/65 = 0.6

To convert a decimal to a percent, multiply the decimal by 100%...

0.6(100%) = 60%

8 0

3 years ago

What's the full equation for this graph?

swat32

1.
Left side of a graph is a line that passes through points $A=(-1,-1)$ and $B=(1,4)$ so we can write its equation as:

$(y-y_A)=\dfrac{y_B-y_A}{x_B-x_A}(x-x_A)\\\\\\
\big(y-(-1)\big)=\dfrac{4-(-1)}{1-(-1)}\big(x-(-1)\big)\\\\\\
y+1=\dfrac{4+1}{1+1}(x+1)\\\\\\y+1=\dfrac{5}{2}(x+1)\\\\\\y+1=\dfrac{5}{2}x+\dfrac{5}{2}\\\\\\y=\dfrac{5}{2}x+\dfrac{5}{2}-1\\\\\\\boxed{y=\frac{5}{2}x+\frac{3}{2}}$

2.
Right side of a graph is a parabola with vertex $V=(3,-3)$ that passes through point $P=(1,1)$ . Its equation:

$y=a(x-x_V)^2+y_V\\\\y=a(x-3)^2+(-3)\\\\y=a(x-3)^2-3$

Substitute $x=1$ and $y=1$ to calculate parameter $a$

$1=a(1-3)^2-3\\\\1=a(-2)^2-3\\\\1=4a-3\\\\4a=4\quad|:4\\\\a=1$

and we have the equation of parabola:

$y=a(x-3)^2-3\\\\y=1\cdot(x-3)^2-3\\\\y=(x-3)^2-3\\\\y=x^2-2\cdot x\cdot3+3^2-3\\\\y=x^2-6x+9-3\\\\\boxed{y=x^2-6x+6}$

From 1. and 2. full equation for graph is:

$f(x)=\begin{cases}\dfrac{5}{2}x+\dfrac{3}{2}\qquad\text{for}\,\,\,x\ \textless \ 1\\\\x^2-6x+6\qquad\text{for}\,\,\,x\geq1\end{cases}$

5 0

4 years ago