Answer:
a. 3942 kWh
b. $473.04
c. 1314 kWh
d. $157.68
Step-by-step explanation:
<h3>a. </h3>
There are 1000 W in 1 kW, so 450 W = 0.450 kW. The energy used per day is ...
(0.45 kW)(24 h) = 10.8 kWh . . . . energy per day
Then in a 365-day year, the energy used is
(365 da/yr)(10.8 kWh/da) = 3942 kWh/yr
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<h3>b.</h3>
At the rate of $0.12/kWh, the cost of running the pump is ...
($0.12/kWh)(3942 kWh/yr) = $473.04/yr
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<h3>c.</h3>
Switching the pump off for 1/3 of the time will save 1/3 of the energy found in part (a):
1/3(3942 kWh) = 1314 kWh . . . . energy saved by switching off the pump
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<h3>d.</h3>
The savings will be 1/3 of the cost of running the pump full time:
1/3($473.04/yr) = $157.68/yr
Answer:
-3
Step-by-step explanation:
it is right
Answer:
the answer is b
Step-by-step explanation:
I got it right on edu2020
-2/1 I did this is math class , we’re on this unit to,
Explanation
Saying it’s a negative number because it is pointing in a left word position, you have to go down twice and over once to find the exact point where the line crosses over a point on the graph, and there you will get -2/1
Remark
Writing down the givens for these questions is almost a command. You must know which equation of the big 4 to use. The givens + what you want to find will determine the equation.
Givens
vi = 30.7 km/hr = 30.7 km/hr *[1000m/1km]*[1hr/3600sec] = 8.52m/sec
vf = 120 km/hr = 120 km/hr * [1000 m/1 km]*[1h/3600 sec] = 33.3 m/s
t = 4.9 seconds
d = ???
Formula
d = (vi + vf)*t/2
Solve
d = ( 33.3+8.52 )*4.9/2
d = (41.85333)*4.9/2
d = 205.02/2
d = 102.51 m<<<Answer
