ASA..........................
The slope (increase) is 0.26 and the y-intercept (start) is 67.6.
You could describe the temperature outside using this equation.
For example, at the beginning of the day, the temperature was 67.6. Then, it increase by 0.26 degree for every given amount of time (minutes or hours).
Answer:
Jenny's room
Step-by-step explanation:
13x12 = 156 and 14x11 = 154
Therefore Jenny's room is bigger.
Answer:
24
Step-by-step explanation:
I have had this question before I know the answer
Answer:
P(Y ≥ 15) = 0.763
Step-by-step explanation:
Given that:
Mean =135
standard deviation = 12
sample size n = 50
sample mean
= 140
Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses
Then,
![X \sim N ( \mu \sigma)](https://tex.z-dn.net/?f=X%20%5Csim%20N%20%28%20%5Cmu%20%5Csigma%29)
The probability that X is greater than 140 is :
P(X>140) = 1 - P(X ≤ 140)
![P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})](https://tex.z-dn.net/?f=P%28X%3E140%29%20%3D%201%20-%20P%28%20%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%20%5Cleq%20%5Cdfrac%7B140-135%7D%7B12%7D%29)
![P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})](https://tex.z-dn.net/?f=P%28X%3E140%29%20%3D%201%20-%20P%28%20%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%20%5Cleq%20%5Cdfrac%7B5%7D%7B12%7D%29)
![P(X>140) = 1 - P( Z\leq0.42)](https://tex.z-dn.net/?f=P%28X%3E140%29%20%3D%201%20-%20P%28%20Z%5Cleq0.42%29)
From z tables,
![P(X>140) = 1 - 0.6628](https://tex.z-dn.net/?f=P%28X%3E140%29%20%3D%201%20-%200.6628)
![P(X>140) = 0.3372](https://tex.z-dn.net/?f=P%28X%3E140%29%20%3D%200.3372)
Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140
Then;
![Y \sim Binomial (np)](https://tex.z-dn.net/?f=Y%20%5Csim%20Binomial%20%28np%29)
![Y \sim Binomial (50,0.3372)](https://tex.z-dn.net/?f=Y%20%5Csim%20Binomial%20%2850%2C0.3372%29)
∴
P(Y ≥ 15) = 1- P(Y< 15)
P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )
![P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49} + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +... + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}](https://tex.z-dn.net/?f=P%28Y%20%5Cgeq%2015%29%20%3D%201%20-%20%5Cbegin%20%7Bpmatrix%7D%20%5E%7B50%7D_0%20%5Cend%20%7Bpmatrix%7D%20%280.3372%29%5E0%20%281-0%2C3372%29%5E%7B50%7D%20%2B%20%5Cbegin%20%7Bpmatrix%7D%20%5E%7B50%7D_1%20%5Cend%20%7Bpmatrix%7D%20%280.3372%29%5E1%20%281-0%2C3372%29%5E%7B49%7D%20%20%2B%20%5Cbegin%20%7Bpmatrix%7D%20%5E%7B50%7D_2%20%5Cend%20%7Bpmatrix%7D%20%280.3372%29%5E2%20%281-0%2C3372%29%5E%7B48%7D%20%2B...%20%20%2B%20%5Cbegin%20%7Bpmatrix%7D%20%5E%7B50%7D_%7B50%7B%20%5Cend%20%7Bpmatrix%7D%20%280.3372%29%5E%7B50%7D%20%281-0%2C3372%29%5E%7B0%7D)
P(Y ≥ 15) = 0.763