Well lets do the math
220 x 8 = 1760
1240 x 2 = 2480
2480 + 1760 = 4240
So we need 2 first class and 8 coach.
Answer:
11/12, 3/4, 5/8, 9/20 (from smallest to biggest)
The dimensions of the package of maximum volume that can be sent are 20 inches by 40 inches.
Let us represent the length of the square cross-section of the postal package with x, and the width of the package with y.
So, the perimeter is given by the equation -
y + 4x = 120
y = 120-4x -----------(1)
the volume will be
V = -----------(2)
Now, substitute (1) in (2), and we get,
V = (120-4x)
V = 120 - 4
Differentiating with respect to x, we get,
V' = 240x - 12
V'=0
hence, 240x - 12 = 0
12 = 240x
dividing by 120x on both sides,
hence, x=20
Now, we know that,
y = 120 - 4x
y = 120-4(20)
y = 120-80
y=40
Hence, the dimensions that maximize the volume of the package are 20 inches by 40 inches.
Read more about maximum volumes:
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There is one 2 in common and there are "x" and "y" variables in common. Finally, the GCF of 18xy and 32xyz is 2xy.
Answer:
90
Step-by-step explanation:
0.1x=9
x=90