the question in English
Juan has blue cubes with a 55 mm edge and red cubes with a 45 mm edge. He stacks them in two columns, one of each color; he wants the two columns to be the same height. How many cubes does he need, as a minimum, of each color?
Let
x---------> the number of blue cubes
y--------> the number of red cubes
we know that
Juan wants that the two columns to be the same height
so

solve for y

I proceed to calculate a table, assuming values of x to calculate the value of y. When the values of x and y are whole numbers, I will have found the solution.
the table in the attached figure
therefore
<u>the answer is</u>
9 blue cubes
11 red cubes
Answer:
Let's name the digit:
x- ones digit
y - tens digit
we know that x=y-2.
Now, y can be 6,7,8,9 (the number is between 60 and 100 (so depending on your understanding of "between", 0 is also possible. but then the number would have to have -2 as its ones digit, so in any case, it's not possible).
So the possibilities with x=y-2:
64
75
86
97
Out of those 64 and 86 are even, so they can't be prime.
75 has 5 in its ones number: it's divisible by 5.
so the correct answer is 97.
Step-by-step explanation:
Hope this helps!
Addition is commutative.
3 + 4 = 7. = 4 + 3
Division is not commutative.
3 / 4 is not = 4 / 3.
An ordered pair of the inverse of f(x)D, (1.2)