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shutvik [7]
3 years ago
14

Omg please help please

Mathematics
1 answer:
Brut [27]3 years ago
4 0

x^{2}Answer:

(Explanation)

Step-by-step explanation:

Part A:

The graph of y = x^{2} + 2 will be translated 2 units up from the graph of y = x^{2}.

If you plug in 0 for x, you get a y-value of 2. The 2 is also not included with the x^{2}, which is why it doesn't translate left.

This is what graph A should look like:

[Attached File]

Part B:

The graph of y = x^{2} - 2 will be translated 2 units down from the graph of y = x^{2}.

If you plug in 0 for x, you get a y-value of -2. The 2 is also not included with the x^{2}, which is why it doesn't translate right.

This is what graph B should look like:

[Attached File]

Part C:

The graph of y = 2x^{2} is a stretched version of the graph y = x^{2}. Numbers that are greater than 1 stretch and open up and numbers less than -1 stretch and open down.

This is what graph C should look like:

[Attached File]

Part D:

The graph of y = \frac{1}{2}x^{2} is a compressed version of the graph y = x^{2}. Numbers that are in-between 0 and 1, and -1 and 0 are compressed.

This is what graph D should look like:

[Attached File]

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3 years ago
Solving systems of equations using any method
andreev551 [17]

Answer:

x = 5 , y = 2

Step-by-step explanation:

Solve the following system:

{y = (7 x)/5 - 5 | (equation 1)

{y = (3 x)/5 - 1 | (equation 2)

Express the system in standard form:

{-(7 x)/5 + y = -5 | (equation 1)

{-(3 x)/5 + y = -1 | (equation 2)

Subtract 3/7 × (equation 1) from equation 2:

{-(7 x)/5 + y = -5 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 1 by 5:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+(4 y)/7 = 8/7 | (equation 2)

Multiply equation 2 by 7/4:

{-(7 x) + 5 y = -25 | (equation 1)

{0 x+y = 2 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(7 x)+0 y = -35 | (equation 1)

{0 x+y = 2 | (equation 2)

Divide equation 1 by -7:

{x+0 y = 5 | (equation 1)

{0 x+y = 2 | (equation 2)

Collect results:

Answer:  {x = 5 , y = 2

7 0
3 years ago
A jar has 6 red marbles and 4 blue marbles. If 2 marbles are chosen, one at a time without replacement, what is the probability
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1/3 Probability both are red

red picked first:

6/10

red picked second:

5/9 (9 as first red marble not replaced so 5 red marbles remaining and 4 blue marbles still)

6/10 * 5/10 = 1/3

Hope that helps!!

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3 years ago
Heron's Formula:
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Answer:

√s(s-a) (s-b) (s-c)

Step-by-step explanation:

123456

herons formula

6 0
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The ratio of the number of cars to the number of motorcycles in a parking lot is 10 : 3. The ratio of the number of motorcycles
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5 because 20:6 is the car to motorcycle. 6:15 is the motorcycle to van. 20÷15=5 ~JZ
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3 years ago
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