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NNADVOKAT [17]
3 years ago
12

Help me please please

Mathematics
1 answer:
harina [27]3 years ago
3 0

Answer:

a)

  • EH = \sqrt{HG^2+EG^2} = \sqrt{4^2+6^2} = \sqrt{16+36} = \sqrt{52} = 2\sqrt{13}

b)

  • EG² = GH*GF
  • EG² = 4*12
  • EG² = 48
  • EG = √48 = 4√3
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Answer:

(no global maxima found)

Step-by-step explanation:

Find and classify the global extrema of the following function:

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Hint: | Global extrema of f(x) can occur only at the critical points or the endpoints of the domain.

Find the critical points of f(x):

Compute the critical points of 4 x^4 - 2 x^3 + x - 5

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x = -0.303504

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16 x^3 - 6 x^2 + 1 exists everywhere

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x = -0.303504

Hint: | Determine the endpoints of the domain of f(x).

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The endpoints of R are x = -∞ and ∞

Hint: | Evaluate f(x) at the critical points and at the endpoints of the domain, taking limits if necessary.

Evaluate 4 x^4 - 2 x^3 + x - 5 at x = -∞, -0.303504 and ∞:

The open endpoints of the domain are marked in gray

x | f(x)

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∞ | ∞

Hint: | Determine the largest and smallest values that f achieves at these points.

The largest value corresponds to a global maximum, and the smallest value corresponds to a global minimum:

The open endpoints of the domain are marked in gray

x | f(x) | extrema type

-∞ | ∞ | global max

-0.303504 | -5.21365 | global min

∞ | ∞ | global max

Hint: | Finally, remove the endpoints of the domain where f(x) is not defined.

Remove the points x = -∞ and ∞ from the table

These cannot be global extrema, as the value of f(x) here is never achieved:

x | f(x) | extrema type

-0.303504 | -5.21365 | global min

Hint: | Summarize the results.

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