I think it’s C
Sorry if it’s wrong
<span>To regroup 378 x 6, you must first establish the place values of each digit. 3 has a place value of 300, because it is in the hundreds column; 7 has a place value of 70 because it is in the tens column; 8 has a place value of 8 because it is in the units column. This means you can regroup 378 x 6 as (300 x 6) + (70 x 6) + (8 x 6). This makes 2,268. </span>
The complex conjugate of a + bi is a – bi, and similarly the complex conjugate of <em><u>a – bi is a + bi. </u></em>
Answer:
<h2>true</h2>
Step-by-step explanation:
4 x 10= 40 so true
Answer:
3125*k^9 + y^3 is an integer my closure property.
but 5^(1/3) is not an integer, which forces z to be irrational.
Note that there is no way an integer value can rationalize 5^(1/3)
Step-by-step explanation:
x^3 = 25z^3 - 5y^3
x^3 = 5 ( 5z^3 - y^3)
x = (5 ( 5z^3 - y^3) )^(1/3) must be an integer
= 5^(1/3) * (5z^3 - y^3)^(1/3)
Then (5z^3 - y^3)^(1/3) = 25*k^3 for some integer k
5z^3 - y^3 = 15625*k^9
5z^3 = 15625*k^9 + y^3
z^3 = 3125*k^9 + (1/5)*y^3
z = ( 3125*k^9 + (1/5)*y^3 )^ ( 1/3)
