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Alchen [17]
3 years ago
14

The crisis in the housing market during the most recent economic recession led to lower vacancy rates in the apartment industry.

This, in turn, has resulted in an increase in monthly rents for apartments. Suppose a random sample of 40 apartments had an average rent of $1,090. Assume the standard deviation for the population of apartment rents is $260. Determine the 98% confidence interval for this sample.
Mathematics
1 answer:
Keith_Richards [23]3 years ago
5 0

Answer:

(994.37, 1185.62)

Step-by-step explanation:

Given that :

Mean (m) = 1090

Standard deviation (s) = 260

Samole size (n) = 40

α = 98%

Using the relation :

Confidence interval = mean ± Error

Error = Zcritical * (standard deviation / sqrt (n))

Zcritical at 98% = 2.326

Error = 2.326 * (260 / sqrt(40))

Error = 95.620951

Hence,

Confidence interval :

Lower boundary = 1090 - 95.620951 = 994.379049

Upper boundary = 1090 + 95.620951 = 1185.620951

(994.37, 1185.62)

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Pie

Answer:

R=(5C/A)-1.5

Step-by-step explanation:

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Which graph models the solution set of 50x + 150y&gt;1500?
hodyreva [135]

Answer:

see attached diagram

Step-by-step explanation:

First, draw the dashed line 50x+150y=1500 (dashed because the inequality is without notion "or equal to"). You can do it finding x and y intercepts.

When x=0, then 150y=1500, y=10.

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Connect points (0,10) and (30,0) to get needed dashed line.

Then determine which region (semiplane) you have to choose. Note that origin's coordinates  (0,0)  do not satisfy the inequality 50x + 150y>1500, because

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This means that origin lies outside the needed region, so you have to choose the semiplane that do not contain origin (see attached diagram).


4 0
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Answer:

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8 I believe if not use the app so socratic
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Answer:

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