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ankoles [38]
3 years ago
6

An object acted on by a constant force F moves from point 1 to point 2 and back again. The work done by the force F in this roun

d trip is 60 J. Can you determine from this information if F is a conservative or nonconservative force?
Physics
1 answer:
aksik [14]3 years ago
7 0

Answer:

F is non-conservative.

If F were conservative no work would be done in moving back to the original point.       F dot S = W     if the net distance is zero the work done is zero for a conservative force

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What is the distance between a(-6,3),b(-2,4),c(-8,3)​
Schach [20]

Answer:

Explanation:

Appears to be the vertexes of a triangle.

AB = √(-6 - (-2))² + (3 - 4)²) = √17

AC = √(-6 - (-8))² + (3 - 3)²) = 2

BC = √(-2 - (-8))² + (4 - 3)²) = √37

8 0
3 years ago
An electron initially 3.00 m from a nonconducting infinite sheet of uniformly distributed charge is fired toward the sheet. The
Cloud [144]

Answer:

4.4443704375\times 10^{-18}\ C/m^2

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

\Delta l = Distance charge traveled = 2 m

v = Velocity of electron = 420 m/s

E = Electric field

m_e = Mass of electron = 9.11\times 10^{-31}\ kg

q_e = Charge of electron = 1.6\times 10^{-19}\ C

As the energy of the system is conserved we have

q_eE\Delta l=\dfrac{1}{2}m_ev^2\\\Rightarrow E=\dfrac{1}{2}\dfrac{m_e}{q_e}\times \dfrac{v^2}{\Delta l}\\\Rightarrow E=\dfrac{1}{2}\dfrac{9.11\times 10^{-31}}{1.6\times 10^{-19}}\times \dfrac{420^2}{2}\\\Rightarrow E=2.51094375\times 10^{-7}\ N/C

For an infinite non conducting sheet electric field is given by

E=\dfrac{\sigma}{2\epsilon}\\\Rightarrow \sigma=2E\epsilon\\\Rightarrow \sigma=2\times 2.51094375\times 10^{-7}\times 8.85\times 10^{-12}\\\Rightarrow \sigma=4.4443704375\times 10^{-18}\ C/m^2

The surface charge density is 4.4443704375\times 10^{-18}\ C/m^2

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Explanation:

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they are constantly bouncing everywhere and creating preasure

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Explanation:

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