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tino4ka555 [31]

3 years ago

15

A ship anchored at sea is rocked by waves that have crests 14 m apart the waves travel at 7.0 m/s how often do the wave crest re

ach the ship

1 answer:

xeze [42]3 years ago

3 0

Answer:

I think its 2 seconds

Explanation:

14/7

You might be interested in

A proton is trapped in a one-dimensional well that is 200 pm wide. What is the ground state energy of the proton, if the potenti

Harrizon [31]

Answer:

E=1.50\times 10^{-18}J

Explanation:

Energy of the one dimensional infinite well,

$E=\frac{n^{2}h^{2} }{8mL^{2} }$

Given that, $L=200 pm\\L=200\times 10^{-12}m$

For the ground state n=1,

Therefore energy is,

$E=\frac{(6.626\times 10^{-34})^{2}}{8(9.1\times 10^{-31})(200\times 10^{-12}) ^{2} }\\E=1.50\times 10^{-18}J$

8 0

3 years ago

Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A pipe closed at both ends can have standing wav

uranmaximum [27]

Answer:

68.8 Hz

137.6 Hz, 206.4 Hz

Explanation:

L = Length of tube = 2.5 m

v = Velocity of sound in air = 344 m/s

Distance between nodes is given by

$L=\dfrac{\lambda}{2}+m\dfrac{\lambda}{2}\\\Rightarrow \dfrac{\lambda(n+1)}{2}=L\\\Rightarrow \lambda=\dfrac{2L}{n+1}$

Where n = 0, 1, 2, 3, ...

Making n+1 = n

$\lambda=\dfrac{2L}{n}$

where n = 1, 2, 3 .....

For fundamental frequency n = 1

$\lambda=\dfrac{2\times 2.5}{1}\\\Rightarrow \lambda=5\ m$

Frequency is given by

$f=\dfrac{v}{\lambda}\\\Rightarrow f=\dfrac{344}{5}\\\Rightarrow f=68.8\ Hz$

The fundamental frequency is 68.8 Hz

First overtone

$2f=2\times 68.8=137.6\ Hz$

Second overtone

$3f=3\times 68.8=206.4\ Hz$

The overtones are 137.6 Hz, 206.4 Hz

4 0

4 years ago

A block, whose mass is 0.500 kg, is attached to a spring with a force constant of 126 N/m. The block rests upon a frictionless,

erastova [34]

Answer:

(a) F = 15.12 N

(b) a = 30.24 m/s²

(c) To Left

Explanation:

(a)

The magnitude of the spring force is given by Hooke's Law as follows:

F = kx

where,

F = Spring Force = ?

k = Spring Constant = 126 N/m

x = Displacement = A = 0.12 m

Therefore,

F = (126 N/m)(0.12 m)

<u>F = 15.12 N</u>

(b)

The magnitude of acceleration can be found by comparing the spring force with the unbalanced force formula of Newton's Second Law:

F = ma

where,

F = Spring Force = 15.12 N

m = mass of block = 0.5 kg

a = magnitude of acceleration = ?

15.12 N = 0.5 kg (a)

a = 15.12 N/0.5 kg

<u>a = 30.24 m/s²</u>

<u></u>

(c)

Since, the acceleration is always directed towards mean (equilibrium) position in periodic motion. Therefore, the direction of the acceleration at the time of release will be <u>to left.</u>

8 0

3 years ago

Which of the following statements is untrue in regard to sound traveling in air?

Olegator [25]

The right answer for the question that is being asked and shown above is that: "d. As the distance from the Earth increases, the sound wave intensity also decreases due to the lessening density." This the <span>statement that is untrue in regard to sound traveling in air</span>

5 0

4 years ago

A trough is 3 meters long, 2 meters wide, and 4 meters deep. The vertical cross-section of the trough parallel to an end is shap

irina1246 [14]

Answer:

work done is 470400 J

Explanation:

given data

long = 3 m

wide = 2 m

deep = 4 m

density = 1000 kg/m³

to find out

Find the amount of work in joules

solution

we know here volume = area × length

so

area = 0.5 ×base×height

area = 0.5 ×2×4

area = 4 m²

so volume = 4 × 3 = 12 m³

and

weight of water = volume ×density×g

weight = 12 × 1000 × 9.8

weight = 117600 N

so

work done = weight × height

work done = 117600× 4

work done = 470400 J

8 0

3 years ago