Answer:
No, projectile launched at 20° landed first.
Explanation:
70° projectile had a vertical velocity of v*sin(70), which is significantly bigger than v*sin(20). Since v=vx+at, we can see that 
solve for t, you can check that by substituting velocity for any number.
Answer:
<h3>
30.66m</h3>
Explanation:
Using the equation of motion formula 
where;
S is the height to which the ball rises
u is the initial velocity of the ball = 0m/s
a is the acceleration due to gravity = 9.81m/s²
t is the time taken by the ball in air = 5.0s
Note that the time to rise to the peak is one-half the total hang-time = 5.0/2 = 2.5s
Substituting the given parameters into the formula above to get S:
This means that the ball rises 30.66m before it reaches its peak.
Answer:
Explanation:
Action and reaction force are an integral part of third law of Newton . They are equal and opposite force - couple which act on two opposite objects. That is why they can not make a body in equilibrium.
In the given case, a bat is hit by a ball , at the point of contact , two equal and opposite forces emerge simultaneously , one acting on the ball and the other acting on the bat. As per the problem , force on the bat is called action . So the other force , that is force acting on the ball is called reaction force.
Answer: I Believe The Answer Is A. Insulating The Body
Answer:
<em>t = 1.02 s</em>
Explanation:
friction = 0 N (no slipping)
downward force along the inclined plane = F = mgsin(30.8)
F = ma
⇒ a = 9.81 sin(30.8)
a = 5.02 m/s^2
now we have
displacement = s = 2.6 m
acceleration = a = 5.02m/s^2
initial velocity = Vi = 0m/s
time = t = ?
<u>APPLYING THE 2ND EQUATION OF MOTION:</u>
<em> S = (Vi)(t)+0.5at^2</em>
<em>2.6 = 0(t) + 0.5 * 5.02 * t^2</em>
<em>t = 1.02 s</em>
