Answer:
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Answer:
moles O₂ needed = 0.19 mole
Explanation:
4Fe(s) + 3O₂(g) => 2Fe₂O₃(s)
1.396g Fe(s) = 1.396g/56g/mol = 0.025 mole Fe(s)
0.025 mole Fe(s) reacts with 3/4(0.025 mole O₂(g) = 0.019 mole O₂(g)
Answer:
2.5 moles of N₂ and 7.5 moles of H₂ entered the reaction
Explanation:
In reaction:
N₂(g) + 3 H₂(g) → 2 NH₃(g)
You can see that the stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) requires the following amounts of reagents and are produced:
- N₂: 1 mole
- H₂: 3 moles
- NH₃: 2 moles
The following three rules can apply:
- If 2 moles of NH₃ are produced from 1 mole of N₂ by stoichiometry of the reaction, 5 moles of NH₃ from how many moles of N₂ are produced?

moles of N₂= 2.5
- If 2 moles of NH₃ are produced from 3 moles of H₂ by stoichiometry of the reaction, 5 moles of NH₃ from how many moles of H₂ are produced?

moles of H₂= 7.5
<u><em>2.5 moles of N₂ and 7.5 moles of H₂ entered the reaction</em></u>
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