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garri49 [273]
3 years ago
9

What is the answer to this question please

Chemistry
2 answers:
sergeinik [125]3 years ago
5 0
Infrared and ultraviolet light
mezya [45]3 years ago
3 0
Infared and ultraviolet light. :)
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3 years ago
How many grams of KF are in 2 liters of a 3.0 M solution of KF
Rufina [12.5K]

Answer:

mass ( g ) = 348 g

Explanation:

First you know : M = mole / volume (L)

in question you have the M and V and the formula of SUBSTANCE ( KF )

first you get the number of mole from equation above

so 3 = no of mole / 2

no of mole = 3 × 2 = 6 moles

and the moles equation is no of moles = mass ( g ) / molecular weight ( g/mole )

so you have already calculate the moles and you can know the MW from the Question

Mw of KF = 39 + 19 = 58

so n = mass / MW

so 6 = mass / 58

mass ( g ) = 348 g

GOOD LUCK

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