Answer:
true
Step-by-step explanation:
Answer:
x = z/(6πy)
Step-by-step explanation:
Divide by the coefficient of x.
z/(6πy) = 6πxy/(6πy)
z/(6πy) = x
Answer:
The distance added to each dimension is 2 yards.
Step-by-step explanation:
The initial dimensions of the rectangular fence is 8 yards by 4 yards.
The initial area of the rectangular fence = area of a rectangle
area of a rectangle = length x width
So that,
The initial area of the fence = 8 x 4
= 32
The initial area of the fence is 32 square yards.
But, with the new dimensions, area = 60 square yards.
(4 + x) x (8 + x) = 60
+ 12x + 28 = 60
+ 12x - 32 = 0
(x + 14) = 0 or (x - 2) = 0
x = -14 or x =2
Thus, x = 2
The distance added to each dimension is 2 yards.
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
