Answer:
-2
Step-by-step explanation:
You make x= -3 then you insert it into the problem which is x= 2(-3)+4
2 times -3 is -6 which then you would get
-6+4 which equals -2
Try this, I think its correct
Answer:
Consistent/Independent, Inconsistent, Dependent
Step-by-step explanation:
<u>Consistent/Independent:</u>
Where there's only one unique solution
<u>Inconsistent</u>
Where there is no solution
<u>Dependent</u>
Where the solution is dependent
B - 13
Okay, we know that Mark brought 1 notebook and the totally is 6.91 while one pencil costs $0.42.
x= number of pencils he brought.
we know the price of 1 notebook + the cost of pencils times the numbers of pencils he brought = total cost.
So the equation will be:
1.45 + 0.42x = 6.91 subtract 1.45 on both sides.
0.42x = 5.46 Then we solve for x by dividing both sides by 0.42
x= 13
So the number of pencils he brought is 13.
Problem 1
<h3>Answer: False</h3>
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Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
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Problem 2
<h3>Answer: True</h3>
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Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
