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love history [14]
3 years ago
13

What do you think causes the difference between the elements on the top of the periodic table, like carbon, with those on the bo

ttom of the periodic table like tin or lead
Chemistry
1 answer:
icang [17]3 years ago
3 0
The amount of orbitals per period (row).
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D

C

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stem, roots, leaves and flower

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60 POINTS + BRAINLIEST !! PLEASE HELP!!
uranmaximum [27]
To get moles. divide mass by molar mass.Molar mass of
Na is 23
and for Cl is 35.5.
the total molar mass of NaCl is 23+35.5 = 58.5mol/gUse the mass and divide by this number30.22g divide by 58.5mol/g and you will get 0.5166 mole.
Since the molecule has 1 Na to 1 Cl, and that the number of moles for NaCL is 0.5166. All of them would be 0.5166molesNa = 0.5166 x 1 = 0.5166molesCl = 0.5166 x 1 = 0.5166moles
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5 0
4 years ago
The idea that an emotion-arousing stimulus is simultaneously routed to the cortex and to the sympathetic nervous system is centr
pshichka [43]
<h3><u>Answer;</u></h3>

Cannon-Bard theory

<h3><u>Explanation</u>;</h3>
  • <em><u>The idea that an emotion-arousing stimulus is simultaneously routed to the cortex and to the sympathetic nervous system is central to the Cannon-Band theory.</u></em>
  • Cannon-Bard theory states that we feel emotions and experience physiological reactions such as sweating, trembling, and muscle tension simultaneously.
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7 0
4 years ago
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blast furnaces give off many unpleasant and unhealthy gases. If the total air pressure is .99 ATM the partial pressure of carbon
kolbaska11 [484]

Answer:

P_{air}=1.02atm

Explanation:

Hello!

In this case, since the Dalton's law help us to realize that the total pressure of a gas mixture is computed by adding the partial pressure of each composing gas, for the mixture formed by carbon dioxide, oxygen sulfide (should be hydrogen sulfide instead) and air, we can write:

P=P_{CO_2}+P_{H_2S}+P_{air}

Thus, given the total pressure and the partial pressures of both carbon dioxide and hydrogen sulfide, the partial pressure of the remaining air would be:

P_{air}=P_{T}-P_{H_2S}-P_{CO_2}

Therefore, we plug in to obtain:

P_{air}=0.99atm-0.05atm-0.02atm\\\\P_{air}=1.02atm

Best regards!

6 0
3 years ago
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