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OLga [1]
3 years ago
10

What is the ratio of Al 3+ ions to S 2- ions in a neutral compound?

Chemistry
2 answers:
iren2701 [21]3 years ago
4 0
In a neutral ionic compound, you can determine its sub-scripts by simply flipping the ionic charges and dropping the signs: so AlS would be Al2S3
mr_godi [17]3 years ago
4 0

Answer:

The ratio of aluminium to sulfur is 2:3

Explanation:

The ratio of the elements of the neutral compound can be computed from the ionic charges that makes up the compound. The element that makes up the compound is aluminium and sulfur.  From the ions aluminium is the cation with a charge of 3+ . The  aluminium ion is the cations because it loses 3 electrons from the bonding between it and sulfur. The sulfur is the anion as it gains electrons from the cations.

Aluminium has a charge of 3+ and sulfur has a charge of 2- . The atom of element that makes up the neutral compound can be computed when you cross multiply the charges.

Al3+ and S2-

cross multiply the charges

Al2S3.

The ratio of aluminium to sulfur is 2:3

 

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What is the chemical formula for sodium sulfate?
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Hello!

When finding the chemical formula of a compound, we will need to find the charges of each element/bond.

Looking at our period table, sodium has a +1 charge, written as Na 1+, and sulfate has a charge of -2, and it is written as SO4 2-.

Now, we need to make the charges equivalent. To do this, we need to "criss-cross" the charges. This means that sodium will need to additional atoms to make the charges equal, and sulfate will need one.

Therefore, the chemical formula for sodium sulfate is: Na2SO4.

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Which of the following is NOT a property of bases? Which of the following is NOT a property of bases? Bases dissolve many metals
Hitman42 [59]

Bases dissolve many metals.

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3 years ago
What type of reaction is represented by the following equation?
professor190 [17]

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Explanation:

7 0
2 years ago
54.56 g of water at 80.4 oC is added to a calorimeter that contains 47.24 g of water at 40 oC. If the final temperature of the s
fomenos

Answer:

49.5J/°C

Explanation:

The hot water lost some energy that is gained for cold water and the calorimeter.

The equation is:

Q(Hot water) = Q(Cold water) + Q(Calorimeter)

<em>Where:</em>

Q(Hot water) = S*m*ΔT = 4.184J/g°C*54.56g*(80.4°C-59.4°C) = 4794J

Q(Cold water) = S*m*ΔT = 4.184J/g°C*47.24g*(59.4°C-40°C) = 3834J

That means the heat gained by the calorimeter is

Q(Calorimeter) = 4794J - 3834J = 960J

The calorimeter constant is the heat gained per °C. The change in temperature of the calorimeter is:

59.4°C-40°C = 19.4°C

And calorimeter constant is:

960J/19.4°C =

<h3>49.5J/°C</h3>

<em />

7 0
3 years ago
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