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OLga [1]
3 years ago
10

What is the ratio of Al 3+ ions to S 2- ions in a neutral compound?

Chemistry
2 answers:
iren2701 [21]3 years ago
4 0
In a neutral ionic compound, you can determine its sub-scripts by simply flipping the ionic charges and dropping the signs: so AlS would be Al2S3
mr_godi [17]3 years ago
4 0

Answer:

The ratio of aluminium to sulfur is 2:3

Explanation:

The ratio of the elements of the neutral compound can be computed from the ionic charges that makes up the compound. The element that makes up the compound is aluminium and sulfur.  From the ions aluminium is the cation with a charge of 3+ . The  aluminium ion is the cations because it loses 3 electrons from the bonding between it and sulfur. The sulfur is the anion as it gains electrons from the cations.

Aluminium has a charge of 3+ and sulfur has a charge of 2- . The atom of element that makes up the neutral compound can be computed when you cross multiply the charges.

Al3+ and S2-

cross multiply the charges

Al2S3.

The ratio of aluminium to sulfur is 2:3

 

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Suppose 12.0 g of carbon (c) reacts with 70.0 g of sulfur (s) to give 76.0 g of the compound carbon disulfide 1 c s 2 2 . In the
Nitella [24]

Answer is: mass of unused sulfur is 5.87 grams.

Balanced chemical reaction: C + 2S → CS₂.

m(C) = 12.0 g; mass of carbon.

m(S) = 70.0 g; mass of sulfur.

n(C) = m(C) ÷ M(C).

n(C) = 12 g ÷ 12 g/mol.

n(C) = 1 mol; amount of substance.

n(S) = m(S) ÷ M(S).

n(S) = 70 g ÷ 32.065 g/mol.

n(S) = 2.183 mol.

From chemical reaction: n(C) : n₁(S) = 1 : 2.

n₁(S) = 1 mol · 2 = 2 mol.

Δn(S) = n(S) - n₁(S).

Δn(S) = 2.183 mol - 2 mol.

Δn(S) = 0.183 mol; amount of unused sulfur.

Δm(S) = 0.183 mol · 32.065 g/mol.

Δm(S) = 5.87 g.

4 0
3 years ago
What would happen to a nucleus containing two or more protons if the strong force was absent?
Otrada [13]
The positively charged protons would repel one another and fly apart, destroying the nucleus.
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2 years ago
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sveticcg [70]

do you mean fractional distillation of crude oil ?

if you do then this is what happens:

basically, crude oil is made up of a lot of hydrocarbons so it's put into a fracitonating column to separate these compounds into fractions. the top of the fractionating column is colder whereas the bottom of the column is hotter.

gases, petrol, diesel and kerosene come out near the top of the top of the column because they are shorter chains. substances near the top of the column also have a lower boiling point (since it's cooler and there's less intermolecular forces).

the substances at the top of the column are typically useful fuels because they have a higher ease of ignition (higher up=easier to ignite, lower down = harder to ignite). Also, substances at the top have a low viscosity so they can flow easily.

substances that come out near the bottom of the fracitonating column include fuel oil and bitumen.

these are longer chains of hydrocarbons and bitumen is used for road surfacing.

these substances have a high viscosity (harder to flow) and have a high boiling point since they have more intermolecular forces which require a lot of energy to break. Also the bottom of the fractionating column is warmer and this is where these fractions are released.

5 0
3 years ago
The density of dry air measured at 25 Celsius is 1.19 times 10 to the negative 3 what is the volume of 50.0g of air
Oksana_A [137]

Answer:

4.2 x 10⁴ mL

Explanation:

Data Given:

Density (d) of air =  1.19 x 10⁻³g/mL

Mass of the air (m) = 50 g

Volume of the air (V) = ?

Solution:

Formula will be used

                d = m/V

As we have to find volume so rearrange the above equation

               V = m/d . . . . . . . . . . . (1)

Put values in above equation 1

                V = 50 g / 1.19 x 10⁻³g/mL

                V = 4.2 x 10⁴ mL

So,

volume of dry air = 4.2 x 10⁴ mL

4 0
3 years ago
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