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3 years ago

The results from Rutherford's alpha particle scattering experiment led to

Physics

1 answer:

Brut [27]3 years ago

7 0

Answer:

Explanation:

Can you help me in mathematics

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Formula One racers speed up much more quickly than normal passenger vehicles, and they also can stop in a much shorter distance.

Afina-wow [57]

Answer

given,

initial speed of the car = 90 m/s

final speed of the car = 0 m/s

distance taken to stop = 110 m

calculating the acceleration of the car = ?

using the equation of motion

v² - u² = 2 a s

0² - 90² = 2 x a x 100

$a = \dfrac{-90^2}{2\times 100}$

a = 40.5 m/s²

acceleration of the formula one car is equal to a = 40.5 m/s²

7 0

3 years ago

How can we reduce the ripple factor of a bridge recitifier from 0.48 to 0.1 approximately ?

padilas [110]

U can try to use capacitor , the value of capacitor depends on circuit

ripple factors signifies the ac components, by def its ratio of rms value of ac component to value of dc component
so in order to reduce use of a capacitor which denies the sudden changes in voltage, which is the charracteristic of Ac signals

hope this helps

4 0

4 years ago

As the temperature of a liquid increases, the solubility of a solid in the liquid

nexus9112 [7]

D, it depends. For water, the solubility increases as it get hotter, up to 100 degrees, but in some cases, liquids behave the opposite way.

4 0

3 years ago

What name is given to the variable we plot on the x axis

faltersainse [42]

Answer:

independent variable

Explanation:

Do u understand?

8 0

3 years ago

How much more light does an 8-meter telescope gather than a 2-meter telescope?

Colt1911 [192]

Answer:

8 meter telescope 16 times more gather light than 2 meter telescope.

Explanation:

The amount of light gather by the telescope is known as Light Gathering Power (LGP).

Light Gathering Power is determine by the relation:

$LGP = \pi \frac{(length\ of\ telescope)^{2} }{4}$

In this problem, let l₁ and l₂ be the length of two telescopes and (LGP)₁ and (LGP)₂ be the light gathering power of two telescopes respectively. Then the ratio of their LGP is :

$\frac{(LGP)_{1} }{(LGP)_{2}} = \frac{l_{1} ^{2} }{l_{2} ^{2}}$

Substitute 8 m for l₁ and 2 m for l₂ in the above equation.

$\frac{(LGP)_{1} }{(LGP)_{2}} = \frac{8 ^{2} }{2 ^{2}}$

$\frac{(LGP)_{1} }{(LGP)_{2}} = 16$

3 0

3 years ago