If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular

Physics

2 answers:

AfilCa [17]3 years ago

7 0

The correct answer is D (just took the test) Good luck!

erastova [34]3 years ago

6 0

Answer;

D. The car would begin to move in the direction it was headed in a straight line.

Explanation;

-Centripetal force is any net force causing uniform circular motion. The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration.

-The centripetal force causing the car to turn in a circular path is due to friction between the tires and the road. A minimum coefficient of friction is needed, or the car will move in a larger-radius curve and leave the roadway.

-Therefore,If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular path were reduced then the car would begin to move in the direction it was headed in a straight line.

You might be interested in

The image above shows a block pulled across a table. The spring scale which measures in Newtons, reads the force resisting the m

yaroslaw [1]

It is b weight force

8 0

2 years ago

A speed-time graph is a horizontal line with a y-value of 4. Which describes the objects motion?

taurus [48]

It means the speed is constant with a value of 4 units.

5 0

3 years ago

Why does light behave as shown in the image when it passes from air to glass?

Leto [7]

B) Light slows down when it passes into a denser medium.

5 0

2 years ago

Read 2 more answers

A circuit has a 9.0 V power supply and two 15 Ω resistors connected in parallel. what is the voltage across each resistor?

Flauer [41]

Answer:

B. 9.0 V

Explanation:

In parallel circuits, the voltage across each circuit is the same across each component, which is also equal to the total voltage of the power supplied. So in this case, the voltage across each resistor is still 9.0V.

The voltage only changes when the resistors can connected in series.

3 0

3 years ago

A point charge of 5.7 µc moves at 4.5 × 105 m/s in a magnetic field that has a field strength of 3.2 mt, as shown in the diagram

Sauron [17]

The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N

<h3>What is magnetic force?</h3>

Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:

$\rm F=qvBsin\theta$