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3 years ago

9

Whats the difference between watts, amps, and volts?

1 answer:

daser333 [38]3 years ago

6 0

Answer:

Watts is Power (W)

Amps is current (A)

Volts is Voltage (v)

Explanation:

Watts is a derived unit of 1 joule per second, and is used to quantify the rate of energy transfer. In SI (standard international) base units, the watt is described as kg⋅m²⋅s⁻³, which can be demonstrated to be coherent by dimensional analysis

An ampere is the unit used to measure electric current. Current is a count of the number of electrons flowing through a circuit. One amp is the amount of current produced by a force of one volt acting through the resistance of one ohm

Volt is the electrical unit of voltage or potential difference (symbol: V). One Volt is defined as energy consumption of one joule per electric charge of one coulomb. 1V = 1J/C. One volt is equal to current of 1 amp times resistance of 1 ohm: 1V = 1A ⋅ 1Ω

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A.Momentum Equation

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Using the momentum equation , momentum is given as

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4 years ago

Read 2 more answers

When you irradiate a metal with light of wavelength 433 nm in an investigation of the photoelectric effect, you discover that a

sergij07 [2.7K]

Answer:

The right solution is:

(a) 2.87 eV

(b) 1.4375 eV

Explanation:

Given:

Wavelength,

= 433 nm

Potential difference,

= 1.43 V

Now,

(a)

The energy of photon will be:

E = $\frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}$

= $4.59\times 10^{-19} \ J$

or,

= $\frac{4.59\times 10^{-19}}{1.6\times 10^{-19}}$

= $2.87 \ eV$

(b)

As we know,

⇒ $Vq=\frac{hc}{\lambda}-\Phi_0$

By substituting the values, we get

⇒ $1.43\times 1.6\times 10^{19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{433\times 10^{-9}}-\Phi_0$

⇒ $\Phi_0=2.3\times 10^{-19} \ J$

or,

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5 0

3 years ago

A 100-turn, 3.0-cm-diameter coil is at rest in a horizontal plane. A uniform magnetic field 60%u2218 away from vertical increase

Xelga [282]

Answer:

Induced emf in the coil, E = 0.157 volts

Explanation:

It is given that,

Number of turns, N = 100

Diameter of the coil, d = 3 cm = 0.03 m

Radius of the coil, r = 0.015 m

A uniform magnetic field increases from 0.5 T to 2.5 T in 0.9 s.

Due to this change in magnetic field, an emf is induced in the coil which is given by :

$E=-NA\dfrac{\Delta B}{\Delta t}$

$E=-100\times \pi (0.015)^2\times \dfrac{2.5-0.5}{0.9}$

E = -0.157 volts

Minus sign shows the direction of induced emf in the coil. Hence, the induced emf in the coil is 0.157 volts.

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4 years ago

If the force of gravity changes what will happen and what would cause it to change?

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We will fall to pluto.

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3 years ago

the distance between two successive troughs of wave is 0.4m. If the frequency of the source is 825Hz, calculate the speed of the

neonofarm [45]

Answer:

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Explanation:

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3 years ago