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pshichka [43]
2 years ago
12

1. 5+8 ÷2-7 12× 3-42+20 please help me now I will report your answer if bad

Mathematics
1 answer:
defon2 years ago
4 0

1. 2

2. 14

5+(8÷2)-7

5+4-7

=2

(12x3) - 42 + 30

36-42+30

=14

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Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr and then for another 2 hours and 5 minutes with a constant
NemiM [27]
The complete question is
<span>Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr and then for another 2 hours and 5 minutes with a constant speed of 12 km/hr what is her average speed for the total trip?</span>

we know that
speed=distance/time

1) Sarah rides her horse for 2 1/6 hrs with a constant speed of 6 km/hr
time=2 1/6 hrs----> 13/6 hrs
speed=6 km/h
distance=speed*time----> 6*(13/6)---> 13 km

2)for another 2 hours and 5 minutes with a constant speed of 12 km/hr
time=2hrs+5 minutes----> 2+(5/60)--> 125/60 hrs
speed=12 km/hrs
distance=speed*time----> 12*(125/60)---> 25 km

3) find the average speed for the total trip
total distance=13 km+25 km----> 38 km
total time=(13/6)+(125/60)----> (10*13+125)/60----> 4.25 hours
speed=38/4.25----> 8.94 km/hrs

the answer is
8.94 km/hrs
7 0
3 years ago
(GIVING BRAINLIEST!!)
Ira Lisetskai [31]

Answer:

IT IS THE ANSWER B) SNOW

6 0
2 years ago
Please help I'm so confused :)
Elza [17]

⇒I will first isolate y together with its coefficient k by placing t^{2} to the right hand side...

ky=x+t^{2}

⇒Now to leave y independent we have to divide ky by the coefficient of y which in this case is k.

⇒Meaning k will divide all the terms in the equation.

\frac{ky}{k} =\frac{x}{k} +\frac{t^{2}}{k} \\y=\frac{x}{k} +\frac{t^{2}}{k}

⇒Attached is the answer.

7 0
10 months ago
Find the zeros, vertical asymptote, horizontal asymptote, slant asymptote, and graphing points.
kramer
Zeroes
set numerator to zero
x^2=0
x=0
zeroes are at (0,0)

HA

for p(x)/q(x)

when degree of p(x)<q(x), HA=0

when degree of p(x)=q(x), HA= leading coef of p(x) divided by leading coef of q(x)

when degree of p(x)>q(x) you probably have a slant assymtote

degrees are same (no slant assymtote)

leading coefs

1/1=1

HA is y=1

does it cross?

1=(x^2)/(x^2-4)

x^2-4=x^2

minus x^2 both sides

-4=0

false, it does not cross the HA



VA

simplify the fraction (it can't)

set the denomenator to zero

(x-2)(x+2)=0

VA's at x=2 and x=-2




so to graph

graph the point (0,0)

draw the lines

y=1

x=-2

x=2

reemmber, plus, minus, plus

so from left, it goes from above the HA right up to the VA of x=-2

then goes upside down U shape in between VA's going through (0,0)

then from top of VA x=2 down to y=1 then gets closer to y=1 but never touches


5 0
3 years ago
How to factor 3n^2+3n-60
sveta [45]
3n^2+3n-60 =\\&#10;3(n^2+n-20)=\\&#10;3(n^2+5n-4n-20)=\\&#10;3(n(n+5)-4(n+5))=\\&#10;3(n-4)(n+5)
6 0
3 years ago
Read 2 more answers
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