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AlekseyPX
4 years ago
9

Jim has $4,200 in his checking account to pay his rent. Each month, $600 is taken out of the account

Mathematics
1 answer:
Allushta [10]4 years ago
5 0

Answer:4200-600m=1800

Step-by-step explanation:

4200-600m=1800

Subtract 4200 from 1800

-600m=-3600

Divide both sides by -600

m=6

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The sum of three consecutive numbers is 12 find the numbers
snow_tiger [21]
Let x,y,z be those numbers.
x+y+z = 12
Since x,y,z are consecutive: y=x+1, and z = x+2
Let's replace y and z by their new values:
x+x+1+x+2=12
3x+3=12
You subtract 3 from each side to get variables on a side, and numbers on the other:
3x=9
You divide both sides by 3:
x=3

y=x+1 = 3+1 = 4
z=x+2 = 3+2 = 5

So the numbers are 3; 4 and 5.

You can re-check your answers (very important):
3+4+5 = 12
3;4;5 are consecutive numbers.
The answer has been approved.

Hope this Helps! :)
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3 years ago
Name the set of 6 consecutive integers starting with -3.
vlabodo [156]
The correct answer is -3 through -6.
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3 years ago
11. What method can be used to prove these two triangles are congruent?
zubka84 [21]
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98 POINTS // PLEASE ANSWER ASAP // NO GUESSING // ANSWER ALL PARTS
Nikolay [14]

Answer:

A) y=.50x+15

B) The graph would be a line starting in the bottom left corner and rising to the upper right, the start of the y axis would be 1, as it represents the miles, and the start of the x axis would be 0.50, as it represents the amount of money charged per mile.

C) If you apply the formula y=mx+b to the equation, you will see that 0.50 is the slope, and 15 is the y-intercept.




3 0
3 years ago
Read 2 more answers
The length of a rectangle is three inches more than the width. the area of the rectangle is 180 inches. find the width of the re
ch4aika [34]

We have a rectangle with length L that is 3 inches more than the width W. Then we can write this as:

L=W+3

The area of the rectangle is 180 square inches.

We have to find the width W.

As the area is equal to the product of the length and the width, we can write this equation and solve for W as:

\begin{gathered} A=180 \\ L\cdot W=180 \\ (W+3)\cdot W=180 \\ W^2+3W=180 \\ W^2+3W-180=0 \end{gathered}

We have a quadratic equation. The roots of this equation will be the mathematical solutions.

We can find the roots using the quadratic formula:

\begin{gathered} W=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ W=\frac{-3\pm\sqrt[]{3^2-4\cdot1\cdot(-180)}}{2\cdot1} \\ W=\frac{-3\pm\sqrt[]{9+720}}{2} \\ W=\frac{-3\pm\sqrt[]{729}}{2} \\ W=\frac{-3\pm27}{2} \\ W_1=\frac{-3-27}{2}=-\frac{30}{2}=-15 \\ W_2=\frac{-3+27}{2}=\frac{24}{2}=12 \end{gathered}

The solutions are W = -15 and W = 12.

The first one is not valid, as W has to be greater than 0.

Then, the solution to our problem is W = 12 in.

Answer: the width is W = 12 inches.

6 0
1 year ago
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