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MatroZZZ [7]
3 years ago
9

A music website offering unlimited listening to subscribers charges a one time fee of $12 to join with an additional $6 per mont

h usage fee.
Anna wants to spend less than $60 for the subscription. Which inequality could be used to determine the number of months (x) that Anna will be able to enjoy the music?

A) 6x + 12 < 60
B) 6x + 12 > 60
C) 6x − 12 < 60
D) 6x + 12 ≥ 60
Mathematics
2 answers:
VladimirAG [237]3 years ago
8 0
A. because is $6 for every month as said in 6x, then an additional 12 for signing up, making 6x + 12 and she wants it to be under $60 so you use the less than sign making 6x+12 <60
eduard3 years ago
6 0

Answer:

Option A.

Step-by-step explanation:

Musical website is offering unlimited listening to subscribers charges a one time fees of $12 joining fees and an additional fees = $6 per month for uses

Let Anna uses the facility for x months.

Then usage charges for x months = $6x

Joining fees = $12

Total charges = $12 + $6x

Since Anna wants to spend less than $60 for the subscription, so the inequality to determine the uses will be

6x + 12 < 60

Option A. is the answer.

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\bold{\text{Answer:}\quad \dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

<u>Step-by-step explanation:</u>

.\quad \dfrac{-5x}{8x+7}-\dfrac{6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}+\dfrac{-6x^3}{3x+1}\\\\\\=\dfrac{-5x}{8x+7}\bigg(\dfrac{3x+1}{3x+1}\bigg)+\dfrac{-6x^3}{3x+1}\bigg(\dfrac{8x+7}{8x+7}\bigg)\\\\\\=\dfrac{-15x^2-5x}{(8x+7)(3x+1)}+\dfrac{-48x^4-42x^3}{(8x+7)(3x+1)}\\\\\\=\large\boxed{\dfrac{-48x^4-42x^3-15x^2-5x}{(8x+7)(3x+1)}}

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