The ratio 2 to 6 can be reduced to 1 to 3. That means for every 3 cups of flour there is one cup of sugar.
Answer:
she has D=40, and Q=60
Step-by-step explanation:
Answer:
<h2>A.Vertical:x=7</h2><h2>Slant:y=x+9</h2>
Step-by-step explanation:




Answer:
16
Step-by-step explanation:
Your weight is (roughly) proportional to the inverse of the square of the distance you are from the center of the earth. If that distance is reduced to 1/4 its previous value, then your weight will be multiplied by the factor ...
1/(1/4)² = 16
You would weigh 16 times as much.
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<em>Additional comment</em>
The distribution of mass within the earth also affects your weight.