Destiny was looking at different stars in the night sky with her telescope and noticed that

Chemistry

1 answer:

jenyasd209 [6]3 years ago

7 0

Answer:

The red stars are stars that were here for a while and the blue ones are just starting out or is made up of a few different gases.

Explanation:

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The rate of disappearance of hbr in the gas phase reaction 2hbr(g)?h2(g)+br2(g) is 0.160 m s-1 at 150°c. the rate of appearance

luda_lava [24]

The reaction rates of the substances whether disappearance of a reactant or the appearance of a product are related to each other by the chemical reaction. The reaction rates are related as follows:

rate = rHBr / 2 = rBr2 = rH2

rH2 = 0.160 / 2 = 0.08 M/s

8 0

3 years ago

What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2

Anarel [89]

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃ + 3H₂ → 3H₂O + W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194 .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass . mol)

0.194 mol . 183.84 g/mol = 35.6 g

3 0

3 years ago

How many atoms are in Sodium, Carbon, Hydrogen, Oxygen, Fluorine, Boron, Lithium, Helium, Phosphorus and Sulfur?

vlada-n [284]

Sodium. 11
Carbon. 12
Hydrogen 1
Oxygen 2
Fluuorine. 14
Boron. 5
Lithium. 6
Helium 3
Phosphorus 15
Sulfur 6

6 0

4 years ago

Chemistry

postnew [5]

There are 48.72 g Fluorine ions

<h3>Further explanation </h3>

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison

%F in CaF₂ :

$\tt \%F=\dfrac{2.Ar~F}{MW~CaF_2}\times 100\%\\\\\%F=\dfrac{2.19}{78}\times 100\5=48.72\%$