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malfutka [58]
3 years ago
14

How would someone describe a passing grade

Chemistry
1 answer:
aliya0001 [1]3 years ago
8 0
A passing grade is a grade that makes a person eligible to go to the next grade.
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Solid strontium chromate, SrCrO4, dissolves into its respective ions at 25°C. Suppose that in a particular solution,
user100 [1]

Answer:

I think it's d but I'm not positive

5 0
2 years ago
Read 2 more answers
Can matter be created or<br> destroyed?<br><br> Yes or No
anzhelika [568]

Answer:

No

Explanation:

The same amount of matter is present before and after chemical and physical changes. Matter cannot be created or destroyed

5 0
2 years ago
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Hey I'm a newbie any help please with this
solniwko [45]
6 A
7 A
8 B
9 B
10 A
11 C
4 0
3 years ago
Problem Page Question It takes to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbo
Marizza181 [45]

This is a incomplete question. The complete question is:

It takes 348 kJ/mol to break a carbon-carbon single bond. Calculate the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon. Round your answer to correct number of significant digits

Answer: 344 nm

Explanation:

E=\frac{Nhc}{\lambda}

E= energy  = 348kJ= 348000 J  (1kJ=1000J)

N = avogadro's number = 6.023\times 10^{23}

h = Planck's constant = 6.626\times 10^{-34}Js&#10;

c = speed of light = 3\times 10^8ms^{-1}

348000=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{\lambda}

\lambda=\frac{6.023\times 10^{23}\times 6.626\times 10^{-34}\times 3\times 10^8}{348000}

\lambda=3.44\times 10^{-7}m=344nm    1nm=10^{-9}m

Thus the maximum wavelength of light for which a carbon-carbon single bond could be broken by absorbing a single photon is 344 nm

5 0
3 years ago
How many molecules of CaCi2 are equivalent to 75.9 grams
horsena [70]
<em>M CaCl₂: 40+(35,5×2) = 111 g/mol</em>


6,02·10²³ molecules ---------- 111g
X molecules --------------------- 75,9g
X = (75,9×<span>6,02·10²³)/111
X = <u>4,116</u></span><span><u>·10²³</u> molecules of CaCl</span>₂

:)
8 0
3 years ago
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