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3 years ago

Twice a certain number x is less than 8. Find the range of values of the number

Mathematics

1 answer:

luda_lava [24]3 years ago

5 0

Answer:

F=2x +2

Step-by-step explanation:

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HELP!!!!!plz!!!!!!ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Ugo [173]

Is it not 2? or half?

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4 years ago

What are the solutions of x^2-2x+37=0?

blsea [12.9K]

Answer:

Answer is x=1+6i x=1-6i

Step-by-step explanation:

3 0

3 years ago

What is the y-intercept of the function, represented by the table of values below? x: -2,1,2,4,7 y: 14,8,6,2,-4

anastassius [24]

Answer:

The y-intercept is at y = 10.

Step-by-step explanation:

It will be between y = 14 and y = 7 because the corresponding x values are -2 and 1.

An increase of 3 units of x gives a decrease of 6 units of y fro the above values.

Then an increase of 1 ( 1 to 2) in x gives decrease in y of 2 (8 to 6). The other values show the same pattern.

So very unit increase in x, the y values change by -2.

So from x = -2 to 0 is +2 units for x and this will be -4 units for y so the y-intercept ( when x = 0) will be at y = 14-4 = 10

y-intercept is (0,10).

7 0

3 years ago

The radius of a cylinder is doubled and its height is halved. Find the ratios of their surface areas.

Inessa [10]

Answer: 1:1

Step-by-step explanation:

Let r be the radius and h be the height of a cylinder.

Formula: Curved surface area of cylinder = $2\pi rh$

Now, if radius of a cylinder is doubled and its height is halved, then new radius will be R= 2r and new height will be $H=\dfrac{1}{2}$

Now, new surface area = $2\pi RH= 2\pi(2r)\dfrac{h}{2}= 2\pi rh$

Ratio of curved surface areas : $\dfrac{\text{Surface area}}{\text{New surface area}}=\dfrac{2\pi rh}{2\pi rh}=\dfrac{1}{1}$

Hence, the ratios of their surface areas = 1:1 .

5 0

3 years ago

2x²-5x-12=0 (simplify solution set)

Arada [10]

Answer:

x = 4 or x = -3/2

Step-by-step explanation:

To simplify and solve this, let's use the quadratic formula.

So the format of a quadratic equation is supposed look like this:

$ax^2+bx+c=0$

Let's find a, b, c:

a is the coefficient of x^2
b is the coefficient of x
c is the constant term

Now let's solve the equation.

Let's solve your equation step-by-step.

2x^2−5x−12=0

For this equation: a=2, b=-5, c=-12

2x^2+−5x+−12=0

Step 1: Use quadratic formula with a=2, b=-5, c=-12.

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-12)} }{2(2)}$

$x=\frac{5\pm\sqrt{121} }{4}$

$x=4$ or $x=\frac{-3}{2}$

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<u>Answer:</u>

x = 4 or x = -3/2

7 0

2 years ago

Twice a certain number x is less than 8. Find the range of values of the number​

Twice a certain number x is less than 8. Find the range of values of the number