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2 years ago

If AB=x+4, BC=2x-10, and AC =2x+1, then find the value for x, AB, BC and AC

Mathematics

1 answer:

pshichka [43]2 years ago

8 0

If A, B and C are collinear, then:

$AB+BC=AC\\\\AB=x+4,\ BC=2x-10,\ AC=2x+1$

substitute:

$(x+4)+(2x-10)=2x+1\\\\(x+2x)+(4-10)=2x+1\\\\3x-6=2x+1\ \ \ |+6\\\\3x=2x+7\ \ \ \ |-2x\\\\x=7\\\\AB=x+4\to AB=7+4=11\\\\BC=2x-10\to BC=2(7)-10=14-10=4\\\\AC=AB+BC\to AC=11+4=15$

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2 years ago

What is 22% of 45<br><br><br><br> what is 32.5% of 250

antoniya [11.8K]

Answer:

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2 years ago

Read 2 more answers

Find the upper limit for the zeros of the function P(x)=4x^4+8x^3-7x^2-21x-9

pishuonlain [190]

Answer:

OPTION B - 2

Step-by-step explanation:

What is the upper limit for the zeros of the function P(x) = 4x^4 + 8x^3 - 7x^2 - 21x - 9. Ans: 2 is an upper limit. Use synthetic division. and the remainder are all positive, 2 is an upper limit.

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2 years ago

Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a

just olya [345]

Answer:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and $X \sim Bin(n=600, p =0.4)$

And we want this probability:

$P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10$

$n(1-p)=600*(1-0.4)=360 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=600*0.4=240$

$\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12$

And then $X \sim N (\mu = 240, \sigma= 12)$

And we are interested on the following probability:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

6 0

3 years ago

Help ASAP and explain why!!!

laila [671]

Answer:

c. Side-Angle-Side

Step-by-step explanation:

Two sides (AB and AC) and an included angle (<BAC) in triangle ∆ABC are congruent to two corresponding sides (AD and AC) and an included corresponding angle (<DAC) in ∆ADC.

Therefore, by the SAS Congruence Theorem, both triangles are congruent.

5 0

2 years ago