The value of 7 is 7 because it is in the ones place
The first false statement in the proof as it stands is in Line 5, where it is claimed that a line of length 2.83 is congruent to a line of length 4.47. This mistake cannot be corrected by adding lines to the proof.
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The first erroneous tactical move is in Line 4, where the length of DE is computed, rather than the length of FD. This mistake can be corrected by adding lines to the proof.
A correct SAS proof would use segment FD in Line 4, so it could be argued that the first mistake is there.
A = first piece, b = second piece, c = third piece
a + b + c = 47
b = 3a
c = 5a + 2
a + (3a) + (5a + 2) = 47.....combine like terms
9a + 2 = 47
9a = 47 - 2
9a = 45
a = 45/9
a = 5 ft
b = 3a.....b = 3(5)....b = 15 ft
c = 5a + 2....c = 5(5) + 2.....c = 25 + 2....c = 27 ft
longest piece (c) = 27 ft
For Data Set B, we see that the data is more varied. The absolute deviations are 4, 3, 2, 5. The average of these absolute deviations is 3.5. MAD_B = (4+3+2+5)/4 =3.5 M ADB
Hence, The average of these absolute deviations is 3.5.
Answer:
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I hope this helps you with your algebra