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3 years ago

5

Point A’ is the image of Point A when point A is rotated about the origin B. What angle in the counterclockwise direction is A r

otated through?

1 answer:

liberstina [14]3 years ago

8 0

Answer:

90 degrees

Step-by-step explanation:

You might be interested in

3 consecutive odd integers such that the sum of twice the first and three times the second is 55 more than twice the third

den301095 [7]

Answer:

Consecutive odd integers are 19 , 21 & 23

Step-by-step explanation:

Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).

According to the question,

$2x + 3(x + 2) = 2(x + 4) + 55$

$= > 2x + 3x + 6 = 2x + 8 + 55$

Eliminating 2x from both the sides,

$= > 3x + 6 = 63$

$= > 3x = 63 - 6 = 57$

$= > x = \frac{57}{3} = 19$

So, the consecutive odd integers are = 19 , 21 & 23.

3 0

2 years ago

How can you tell from the equation of a rational function if the function has a hole in the graph ( a removable discontinuity) a

Eva8 [605]

Consider that,

x^2+4x+4 = (x+2)(x+2)

x^2+7x+10 = (x+2)(x+5)

Dividing those expressions leads to

(x^2+4x+4)/(x^2+7x+10) = (x+2)/(x+5)

The intermediate step that happened is that we have (x+2)(x+2) all over (x+2)(x+5), then we have a pair of (x+2) terms cancel as the diagram indicates (see below). This is where the removable discontinuity happens. Specifically when x = -2. Plugging x = -2 into (x+2)/(x+5) produces an output, but it doesn't do the same for the original ratio of quadratics. So we must remove x = -2 from the domain.

5 0

3 years ago

Given the system of constraints name all vertices. Then find the maximum value of the given objective

larisa86 [58]

Answer:

$35$

Step-by-step explanation:

The constraints are

The red line represents the function

$y\leq \dfrac{1}{3}x+1$

At $y=0$

$0=\dfrac{1}{3}x+1\\\Rightarrow -1=\dfrac{1}{3}x\\\Rightarrow x=-3$

At $x=0$

$y=0+1\\\Rightarrow y=1$

Two points are $(-3,0),(0,1)$

The blue line represents the function

$5\geq y+x$

at $y=0$

$5=x$

at $x=0$

$y=5$

Two points are $(5,0),(0,5)$

The other two constraints are $x\geq 0$ , $y\geq 0$ . So, the point has to be in the first quadrant

From the graph it can be seen there are two points where the function will be maximum let us check them.

$(3,2)$

$7x-2y=7\times 3-2\times 2=17$

$(5,0)$

$7x-2y=7\times 5-2\times 0=35$

So, the maximum value of the function is $35$ .

3 0

3 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0

3 years ago

serg [7]

Answer:

Step-by-step explanation:

4/7 x + 70 cm^3 = 3/4 x Subtract 4/7 x from both sides

3/4 x - 4/7 x = 70 cm^3 The lowest common denominator is 28

$\frac{3*7*x}{4*7} - \frac{4*4x}{4*7} = 70 cc\\\frac{21*x}{28} - \frac{16*x}{28} = 70 cc\\\frac{5x}{28}= 70cc\\$

5x = 70*28

5x = 1960 Divide by 5

x = 1960/5

x = 392 cc

7 0

3 years ago

Read 2 more answers