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Allushta [10]
3 years ago
14

An angle measures 46° more than the measure of its supplementary angle. What is the measure of each angle?

Mathematics
1 answer:
Alona [7]3 years ago
6 0

Answer:

67 degree

113 degree

Step-by-step explanation:

Supplementary angles are angles that measure up to 180 degrees. For example, if one angle measures 60 degree, the other angle would measure (180 - 60) 120 degrees

Let x represent the smaller angle

The bigger angle = x + 46

We know that both the smaller and the bigger angle would add up to 180, thus this equation can be written :

x + 46 + x = 180

2x + 46 = 180

Collect like terms

2x = 180 - 46

2x = 134

Divide both sides by 2

x = 67 degrees

the bigger angle = 67 + 46 = 113 degree

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6 0
3 years ago
The height (in meters) of a projectile shot vertically upward from a point 4 m above ground level with an initial velocity of 25
Assoli18 [71]

Answer:

(a) The velocity after 2 second is 5.9 m/s

The velocity after 4 second is -13.7 m/s.

(b) The projectile reaches its maximum height  after 2.60 s of projection.

(c)The maximum height that is attained by the projectile is 37.18 m.

(d)Therefore the projectile hits the ground after 5.36 seconds of projection.

(e)The velocity of the projectile when it hits the ground is 27.03 m/s

Step-by-step explanation:

Given that, a projectile shot vertically upward from a point 4 m above the ground with a initial velocity of 25.5 m/s.

The height of the projectile after t seconds is

h=4+25.5t-4.9t^2

where h is in meter.

(a)

We use the formula

v=u+at

V= final velocity

u = initial velocity = 25.5 m/s

a = acceleration=   acceleration due to gravity= 9.8 m/s²

Since the object moves upward direction and acceleration due to gravity is downward direction. So here a= -9.8 m/s.

v(2)= 25.5+(-9.8)×2

     =25.5-19.6

     =5.9 m/s

And when t= 4

v(4)= 25.5+(-9.8)×4

    =25.5-39.2

    = -13.7 m/s

The velocity after 2 second is 5.9 m/s

The velocity after 4 second is -13.7 m/s.

(b)

At its maximum height,the velocity of the projectile is zero. i.e v=0

∴0=25.5+(-9.8)t

⇒9.8t=25.5

\Rightarrow t=\frac{25.5}{9.8}

⇒t = 2.60 s

The projectile reaches its maximum height  2.60 s after projection.

(c)

To find the maximum height, we are putting t= 2.60 in this equation h=4+25.5t-4.9t^2.

\therefore h= 4+(25.5\times 2.60)-(4.9\times 2.60^2)

     =37.18 m

The maximum height that is attained by the projectile is 37.18 m.

(d)

When the projectile hits the ground the height will be zero i.e h=0

From the equation of height we get

\therefore h=0=4+25.5t-4.9t^2

\Rightarrow 4+25.5t-4.9t^2=0

\Rightarrow t=\frac{-25.5\pm\sqrt{25.5^2-4(-4.9).4}}{2(-4.9)}

⇒t= -0.15 ,5.36

Therefore it hits the ground after 5.36 seconds of projection.

(e)

To find the velocity we use the formula v=u+at

Here v = final velocity=?

u=25.5 m/s,

t = 5.36 s

a= -9.8m/s²

v=25.5+(-9.8)5.36

 = -27.03 m/s

Negative sign denoted that the motion of the projectile is downward direction.

The velocity of the projectile when it hits the ground is 27.03 m/s.

6 0
3 years ago
-2x+3y=-12 2x+y=4 After adding the two equations to eliminate x you are left with 4y=-8 Solve for y: y =
Marina86 [1]

Answer:

y = -2

Step-by-step explanation:

y = -8/4 = -2

3 0
3 years ago
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ollegr [7]

No because 5^2 +10^2 is not equavalent to 13^2

by using the pythagoras' theorem

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Snail C moves 1 inch in 15 minutes how far can snail C travel in half an hour
Nutka1998 [239]

Answer:

2 inches

Step-by-step explanation:

Snail C moves 1 inch every 15 mins. Since half an hour is 30 mins, 30 / 15 = 2.

15 mins + 15 mins = there for your answer is 2 inches in half an hour.

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