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skad [1K]
3 years ago
8

Which element below has the highest electronegativity? beryllium, carbon, fluorine, nitrogen

Chemistry
2 answers:
r-ruslan [8.4K]3 years ago
7 0

Answer: fluprine

Hope this help

Elodia [21]3 years ago
3 0

Answer:

C. Fluorine

Explanation:

I completed the assignment on E.D.G.E.N.U.I.T.Y

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Rank the nonmetals in each set from most reactive (1) to least reactive (3). bromine chlorine iodine
Anettt [7]

Answer:

The answer is b

Explanation:

have common properties and are good conductors of heat and electricity. They reflect light and are malleable, and ductile.

3 0
4 years ago
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2 HBr(g)+O2(g)—>H2O2(g)+Br2(g)
MrRissso [65]

Answer:

b

Explanation:

8 0
3 years ago
What is the atomic number of the yet-undiscovered element directly below francium ( Fr) in the periodic table?
kakasveta [241]
The atomic number of Francium is 87.
4 0
3 years ago
For below checmical equation (which may or may not be balanced), list the number of each type of atom on each side of the equati
Olegator [25]

Answer:

Left hand side:-

Carbon - 12

HYdrogen - 28

Oxygen - 38

Right hand side:-

Carbon - 12

Hydrogen - 28

Oxygen - 38

Since, the number of atoms each side are equal, the reaction is balanced.

Explanation:

The given reaction is:-

2C_6H_{14}_{(l)}+19O_2_{(g)}\rightarrow 12CO_2_{(g)}+14H_2O_{(g)}

Left hand side:-

Carbon - 12

HYdrogen - 28

Oxygen - 38

Right hand side:-

Carbon - 12

Hydrogen - 28

Oxygen - 38

<u>Since, the number of atoms each side are equal, the reaction is balanced.</u>

5 0
3 years ago
Pure ethylene glycol, , is added to 2.00 kg of water in the cooling system of a car. The vapor pressure of the water in the syst
spayn [35]

Answer:

1367.7 g of ethylene glycol was added to the solution

Explanation:

In order to find out the mass of glycol we added, we apply the colligative property of lowering vapor pressure: ΔP = P° . Xm

ΔP = Vapor pressure of pure solvent (P°) - Vapor pressure of solution(P')

525.8 mmHg - 451 mmHg = 451 mmHg . Xm

74.8 mmHg / 451 mmHg = Xm → 0.166 (mole fraction of solute)

Xm = Mole fraction of solute / Moles of solute + Moles of solvent

We can determine the moles of solvent → 2000 g . 1  mol/18 g = 111.1 mol

(Notice we converted the 2kg of water to g)

0.166 = Moles of solute / Moles of solute + 111.1 moles of solvent

0.166 (Moles of solute + 111.1 moles of solvent) = Moles of solute

18.4 moles = Moles of solute - 0.166 moles of solute

18.4 = 0.834 moles of solute → Moles of solute = 18.4/0.834 = 22.06 moles

Let's convert the moles to mass → 62 g/mol . 22.06 mol = 1367.7 g

6 0
3 years ago
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