Answer:
is the concentration of
in the solution.
Explanation:
![Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)](https://tex.z-dn.net/?f=Ni%5E%7B2%2B%7D%28aq%29%20%2B%203%20en%5Crightleftharpoons%20%5BNi%28en%29_3%5D%5E%7B2%2B%7D%28aq%29)
Concentration of nickel ion = ![[Ni^{2+}]=x](https://tex.z-dn.net/?f=%5BNi%5E%7B2%2B%7D%5D%3Dx)
Concentration of nickel complex= ![[[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L](https://tex.z-dn.net/?f=%5B%5BNi%28en%29_3%5D%5E%7B2%2B%7D%5D%3D%5Cfrac%7B0.16%20mol%7D%7B2%20L%7D%3D0.08%20mol%2FL)
Concentration of ethylenediamine = ![[en]=\frac{0.80 mol}{2 L}=0.40 mol/L](https://tex.z-dn.net/?f=%5Ben%5D%3D%5Cfrac%7B0.80%20mol%7D%7B2%20L%7D%3D0.40%20mol%2FL)
The formation constant of the complex = 
The expression of formation constant is given as:
![K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}](https://tex.z-dn.net/?f=K_f%3D%5Cfrac%7B%5B%5BNi%28en%29_3%5D%5E%7B2%2B%7D%5D%7D%7B%5BNi%5E%7B2%2B%7D%5D%5Ben%5D%5E3%7D)



is the concentration of
in the solution.
Answer:
carbon
Explanation:
tbh im not sure just guessing
Answer:
When this equation is solved, the two values of the unknown are 0.0643 and -0.082
Explanation:
Given
--- the actual equation
Required
The values of x
We have:

Cross Multiply

Multiply both sides by 100

Open bracket

Rewrite as:

Using quadratic formula:

Where:

So, we have:



Split



Answer:
The correct option is A
Explanation:
Some amino acids, called glucogenic amino acids, when catabolized convert there carbon backbones to tricarboxylic acid (TCA) cycle intermediates. These intermediates can be subsequently metabolized into carbon dioxide and water with the release of ATP or the formation of glucose (known as gluconeogenesis.
<u>All amino acids (with the exception of leucine and lysine) are glucogenic and can thus generate the carbon backbones required for gluconeogenesis</u>. Thus, the correct option is a.
<h3><u>Answer;</u></h3>
= 9.45 × 10^23 molecules
<h3><u>Explanation; </u></h3>
The molar mass of Na2SO4 = 142.04 g/mol
Number of moles = mass/molar mass
= 223/142.04
= 1.57 moles
But;
1 mole = 6.02 × 10^23 molecules
Therefore;
1.57 moles = ?
= 1.57 × 6.02 × 10^23 molecules
<u>= 9.45 × 10^23 molecules </u>