Parallel:
y
=
2
3
x
−
11
3
y=
3
2
x−
3
11
perpendicular:
y
=
−
3
2
x
+
5
y=−
2
3
x+5
Answer:
432 in.^2
Step-by-step explanation:
The side of the suitcase is a rectangle. One length is 24 inches. The diagonal of the rectangle is 30 inches long. The diagonal is a hypotenuse of a right triangle. The length is a leg. We need to find the other leg.
We use the Pythagorean theorem,
a^2 + b^2 = c^2
(24 in.)^2 + b^2 = (30 in.)^2
576 in.^2 + b^2 = 900 in.^2
b^2 = 324 in.^2
b = sqrt(324 in^2)
b = 18 in
area of rectangle = length * width
A = 24 in. * 18 in.
A = 432 in.^2
Answer:
see below
Step-by-step explanation:

Think of the above as:
* 
=
* 
=
* 
=
* 
= 
= 
Can flip it around to be...

We will find the answer using the second law of motion i.e. Force is equal to the product of mass and acceleration.

Where,
- F is force
- M is mass
- A is acceleration
In our case,
Let's solve for M ~




<em>Thus, The mass of object is 36.36 </em><em>grams</em><em>.</em><em>.</em><em>.</em><em>~</em>