3 years ago

Are These two aright?

Mathematics

1 answer:

Over [174]3 years ago

3 0

Answer:

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Step-by-step explanation:

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An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes. The results wer

liraira [26]

Step-by-step explanation:

since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

$\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1$

So probabaility for $\mathrm{X}=1$ is

$P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679$

So expected frequency for $X=1$ is $0.3679^{*} 30=11.037$ (or $\left.11.04\right)$ .

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Papessa [141]

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attached below

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Alexxandr [17]

Step-by-step explanation:

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kondor19780726 [428]

C^2/f^2

hope that helps

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3 years ago

Are These two aright?​

Are These two aright?