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ryzh [129]
3 years ago
12

Steve wants to open a savings account. Bank A will increase the interest rate on the savings account by

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
7 0

Answer:

Bank A

Step-by-step explanation:

Get them wrong then push try agian and remember it hope it helps?

thats my trick sometimes!

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STUDY<br> 1. Simplify the expression below<br> 5p + 14p<br> 4(x - 2) + 6x<br> 2. Evaluate
melisa1 [442]

Answer:

(11)(B) Simplify numeric and algebraic expressions using the laws of exponents, including integral ... Evaluate the expression for d = -2, d = 0, and d = 1.

Step-by-step explanation:

3 0
3 years ago
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Perimeter refers to the distance around 2-D figure and calculate perimeter, add the side lengths of the figure
viva [34]

Answer:

True

Step-by-step explanation:

The perimeter is the combined length of all the side lengths of a figure.

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3 years ago
Factor Quadratics
icang [17]

Answer:

Step-by-step explanation:

x^2 + 17x + 60

(x + 12)(x + 5)

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3 years ago
How much should a family deposit at the end of every 6 months in order to have $4000 at the end of 3 years? The account pays 5.9
ra1l [238]

We are asked to determine the present value of an annuity that is paid at the end of each period. Therefore, we need to use the formula for present value ordinary, which is:

PV_{ord}=C(\frac{1-(1+i)^{-kn}}{\frac{i}{k}})

Where:

\begin{gathered} C=\text{ payments each period} \\ i=\text{ interest rate} \\ n=\text{ number of periods} \\ k=\text{ number of times the interest is compounded} \end{gathered}

Since the interest is compounded semi-annually this means that it is compounded 2 times a year, therefore, k = 2. Now we need to convert the interest rate into decimal form. To do that we will divide the interest rate by 100:

\frac{5.9}{100}=0.059

Now we substitute the values:

PV_{ord}=4000(\frac{1-(1+0.059)^{-2(3)}}{\frac{0.059}{2}})

Now we solve the operations, we get:

PV_{\text{ord}}=39462.50

Therefore, the present value must be $39462.50

8 0
2 years ago
How do I solve this?
Sonbull [250]

The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.

sec(<em>x</em>) = csc(<em>x</em>)

By definition of secant and cosecant,

1/cos(<em>x</em>) = 1/sin(<em>x</em>)

Multiply both sides by sin(<em>x</em>) :

sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)

As long as sin(<em>x</em>) ≠ 0, this reduces to

sin(<em>x</em>)/cos(<em>x</em>) = 1

By definition of tangent,

tan(<em>x</em>) = 1

Solve for <em>x</em> :

<em>x</em> = arctan(1) + <em>nπ</em>

<em>x</em> = <em>π</em>/4 + <em>nπ</em>

(where <em>n</em> is any integer)

In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of

<em>x</em> = <em>π</em>/4   <u>or</u>   <em>x</em> = 5<em>π</em>/4

5 0
3 years ago
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