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maks197457 [2]
3 years ago
15

A rectangle has side lengths 2x + 3 and 5x - 2.

Mathematics
1 answer:
xz_007 [3.2K]3 years ago
5 0

Answer:

10x² + 11x - 6

Step-by-step explanation:

The area (A) is the product of the sides, that is

A = (2x + 3)(5x - 2) ← expand using FOIL

   = 10x² - 4x + 15x - 6 ← collect like terms

   = 10x² + 11x - 6

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harkovskaia [24]

Answer:

10÷7 = 1 3/7

3÷15= 1/5

3÷5= 3/5

7÷10= 7/10

Step-by-step explanation:

8 0
2 years ago
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Write 9,862,000 in scientific notation.
inn [45]
9,862,000 in scientific notation is 9.862 × 10^6
8 0
3 years ago
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A regular hexagon is dilated by a scale factor of 75 to create a new hexagon. How does the perimeter of the new hexagon compare
mezya [45]
Let the length of the original hexagon be x:
the perimeter of the hexagon will be:
P=length*number of sides
P=6*x=6x
After the dilation the new length became:
length=scale factor × original length
=75 × x
=75x
thus the new perimeter will be:
6×75x
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450x/6x
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3 0
3 years ago
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Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
2 years ago
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1) x = 190 dgrees
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